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anonymous

  • one year ago

CAN SOMEONE HELP ME WITH A SIMPLE TRIG PROBLEM!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    SIMPLE?

  3. anonymous
    • one year ago
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    I am sorry m8 Can't help

  4. Saiyan
    • one year ago
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    im only in Algebra 2

  5. anonymous
    • one year ago
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    SOMEONE?

  6. freckles
    • one year ago
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    Not sure which one you need help with.

  7. freckles
    • one year ago
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    part a) just look for graph that matches y=5 sin(x+pi) let's try to draw a graph here. the amp=5 the period=2pi the phase shift is -pi can you graph y=5sin(x+pi)?

  8. anonymous
    • one year ago
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    1st questions answer looks like option A

  9. anonymous
    • one year ago
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    @freckles so the answer to prt a of the question is answer choice "A"

  10. freckles
    • one year ago
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    yes that looks good you can also plug in numbers like 0 and -pi/2 and -pi and so on to help you pick out the right one

  11. freckles
    • one year ago
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    what are the x-intercepts of y=5sin(x+pi) in that graph

  12. anonymous
    • one year ago
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    so part a is "A"

  13. anonymous
    • one year ago
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    I dont know what the x intercepts are

  14. freckles
    • one year ago
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    do you know hot solve sin(x+pi)=0?

  15. anonymous
    • one year ago
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    yes

  16. freckles
    • one year ago
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    that will give you the x-intercepts if it isn't clear from the graph A

  17. anonymous
    • one year ago
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    so that is answer choice C

  18. freckles
    • one year ago
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    |dw:1438062133167:dw| hmmm... you should know that sin(2pi+pi)=0 and sin(pi+pi)=0 and sin(0+pi)=0 and sin(-pi+pi)=0 and sin(-2pi+pi)=0 and sin(-3pi+pi)=0

  19. freckles
    • one year ago
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    |dw:1438062355237:dw| this is what the graph should look like if it is not clear where the max values are 5 and the min values are -5

  20. freckles
    • one year ago
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    the x-intercepts is where the graph touches the x-axis

  21. anonymous
    • one year ago
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    Oh so the answer choice is B

  22. freckles
    • one year ago
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    yes

  23. freckles
    • one year ago
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    let's look at graphing y=5csc(x+pi) not recall csc and sin are reciprocals of each other so sin(x+pi) will be reciprocal value of csc(x+pi) for x if sin is 0 then csc is what?

  24. freckles
    • one year ago
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    the only number that doesn't have a reciprocal is 0 right?

  25. freckles
    • one year ago
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    so when sin is 0 you have a vertical asymptote for csc

  26. freckles
    • one year ago
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    |dw:1438062590122:dw|

  27. freckles
    • one year ago
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    but say sin is 1 then csc is ?

  28. freckles
    • one year ago
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    remember sin and csc are reciprocal functions

  29. freckles
    • one year ago
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    just flip the number

  30. anonymous
    • one year ago
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    1

  31. freckles
    • one year ago
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    right and 5(1)=5 so both sin and csc will share the following common points |dw:1438062820709:dw|

  32. freckles
    • one year ago
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    we also know if sin is -1 then csc is -1 so we know that the graph will also share |dw:1438062857511:dw|

  33. freckles
    • one year ago
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    now just draw the little U things in between the broken lines so that it is getting closer and not touching

  34. freckles
    • one year ago
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    |dw:1438062900051:dw|

  35. anonymous
    • one year ago
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    ok so those are the relative maximum and minimum points

  36. freckles
    • one year ago
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    the maxes of the sin function are the relative mins of the csc function the mins of the sin function are the relative maxs of the csc function

  37. anonymous
    • one year ago
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    so what are the coordinates of the relative maximum and minimums of the csc function, im sorry im not tryng to get all the answers out of you because there is another problem just like this and I would like to finish this one fast to see if I can do the next one!

  38. freckles
    • one year ago
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    so a relative min/max occurs when the graph is turning but the difference is on that turn if the turn point is above all other points on the subinterval then it is a relative max but if the turn point is below all other points on the subinterval then it is a relative min for example |dw:1438063333098:dw|

  39. freckles
    • one year ago
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    the graph I recently drawed you shows the relative min and max of y=5csc(x+pi)

  40. freckles
    • one year ago
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    it is the curve that is black the green one was the sin function (well the asymptotes are also in green but oh well)

  41. freckles
    • one year ago
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    hint: |dw:1438063498596:dw|

  42. freckles
    • one year ago
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    the y coordinates should be clear

  43. freckles
    • one year ago
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    the x-coordinate occur midpoint of the zeros

  44. anonymous
    • one year ago
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    ok, one sec

  45. anonymous
    • one year ago
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    i think I know the x coordinate for the relative max and min, but i don't know the y coordinate

  46. freckles
    • one year ago
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    |dw:1438063591229:dw|

  47. freckles
    • one year ago
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    the y's are the easiest though :p

  48. freckles
    • one year ago
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    |dw:1438063703129:dw| so this graph didn't make any sense?

  49. freckles
    • one year ago
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    like you see the y=5 line that is where the relative mins of y=5csc(x+pi) occur and the y=-5 line that is where the relative maxs of y=5csc(x+pi) occur

  50. freckles
    • one year ago
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    any point laying on the y=5 line has y-coordinate 5 any point laying on the y=-5 line has y-coordinate -5

  51. anonymous
    • one year ago
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    i see, ok so let me tell you the relative mins and max's

  52. anonymous
    • one year ago
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    (-5pi/2,5) and (-pi/2,5) are the minnimums

  53. freckles
    • one year ago
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    |dw:1438063960901:dw| nice those points are lowest on those little intervals there

  54. anonymous
    • one year ago
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    (-3pi/2,-5) and (pi/2,-5) are the maximums

  55. freckles
    • one year ago
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    |dw:1438063992827:dw| right those points are highest on those little interval there