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anonymous

  • one year ago

1+cos(8x)= A. 4cos(2x) B. 2sin^2(4x) C.4sin(2x) D.2cos^(4x)

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  1. arindameducationusc
    • one year ago
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    cos 2x=1-2sin^2x

  2. arindameducationusc
    • one year ago
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    use this

  3. lυἶცἶ0210
    • one year ago
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    Try using \(\large cos^2x = \frac{1}{2} (1+cos(2x)) \)

  4. anonymous
    • one year ago
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    but how would I use it?

  5. arindameducationusc
    • one year ago
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    there is another identity... cos2x=2cos^2x-1

  6. anonymous
    • one year ago
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    I'm sorry, I'm really confused

  7. arindameducationusc
    • one year ago
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    Answer is D, see how....

  8. arindameducationusc
    • one year ago
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    cos2x=2cos^2x-1 =>1+cos2x=2cos^2x now instead of 2x put 8x(left side) so in the right side its half of 8 that is 4. Got it?

  9. anonymous
    • one year ago
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    yeah, i think so. thanks!

  10. arindameducationusc
    • one year ago
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    My pleasure

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