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anonymous
 one year ago
Find the most general antiderivative of the function. G ( t ) = 4 + t + t^2/ sqrt t
anonymous
 one year ago
Find the most general antiderivative of the function. G ( t ) = 4 + t + t^2/ sqrt t

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[G(t) = 4+t+ \frac{ t^2 }{ \sqrt{t} }\] we can write this as \[G(t) = 4+t+t^{3/2}\] so what do you get when you integrate this expression \[\int\limits (4+t+t^{3/2}) dt\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I wonder if the whole thing is over sqrt t, or just that...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[G(t) = \frac{ 4+t+t^2 }{ \sqrt{t} }\] if so, we can split them up or express it as \[\int\limits (4+t+t^2)t^{1/2} dt\]
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