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anonymous
 one year ago
Challenge! Ready? the length of the hypotenuse of a 30 degrees60 degrees90 degrees triangle is 18. What is the perimeter?
anonymous
 one year ago
Challenge! Ready? the length of the hypotenuse of a 30 degrees60 degrees90 degrees triangle is 18. What is the perimeter?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How irritating. It isn't even that hard.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.042.58. Is this the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey m8 can you help me after youre done with her? :)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0yes... @frankwillfindyou

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's not the answer.

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Well, the excercise in not wellwritten because you have to specify the relative position of the angles. Any how, I'll just call them "alpha" and "beta" so you can give them any order you like and still get the answer. So you have a triangle that you don't know the catets but know the hypotenuse, you can use trigonometry to find the length of those sides: \[ \alpha \in \mathbb{R} / \alpha = k\] \[\beta \in \mathbb{R} / \beta = C\] So, what I mean with this is that you can choose wheter k is 30 or 60 and same goes for C. So, setting that aside, and having the condition that alpha has catet "a" as opposite catet: \[\sin \alpha = \frac{ a }{ 18 } \rightarrow a=18\sin \alpha \] Analogical for catet "b", supposing it's the opposite catet of beta: \[\sin \beta = \frac{ b }{ 18 } \rightarrow b=18 \sin \beta \] The perimeter will be the sum of the length of all the sides of the triangle: \[P _{\triangle}= (18)+(18\sin \alpha)+ (18\sin \beta)\] \[P _{\triangle}=18(1+\sin \alpha + \sin \beta)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are doing it right so far.

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0That's the answer for the possible scenarios of the triangle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438075864983:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its going to have this at the end

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I'm pretty sure it does, but you can't ask a geometry excercise without a diagram, or at least defining the components of the triangle with letters.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that but what is the answer?
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