Challenge! Ready? the length of the hypotenuse of a 30 degrees-60 degrees-90 degrees triangle is 18. What is the perimeter?

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Challenge! Ready? the length of the hypotenuse of a 30 degrees-60 degrees-90 degrees triangle is 18. What is the perimeter?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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How irritating. It isn't even that hard.
42.58. Is this the answer?
hey m8 can you help me after youre done with her? :)

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Other answers:

That's not the answer.
Well, the excercise in not well-written because you have to specify the relative position of the angles. Any how, I'll just call them "alpha" and "beta" so you can give them any order you like and still get the answer. So you have a triangle that you don't know the catets but know the hypotenuse, you can use trigonometry to find the length of those sides: \[ \alpha \in \mathbb{R} / \alpha = k\] \[\beta \in \mathbb{R} / \beta = C\] So, what I mean with this is that you can choose wheter k is 30 or 60 and same goes for C. So, setting that aside, and having the condition that alpha has catet "a" as opposite catet: \[\sin \alpha = \frac{ a }{ 18 } \rightarrow a=18\sin \alpha \] Analogical for catet "b", supposing it's the opposite catet of beta: \[\sin \beta = \frac{ b }{ 18 } \rightarrow b=18 \sin \beta \] The perimeter will be the sum of the length of all the sides of the triangle: \[P _{\triangle}= (18)+(18\sin \alpha)+ (18\sin \beta)\] \[P _{\triangle}=18(1+\sin \alpha + \sin \beta)\]
You are doing it right so far.
That's the answer for the possible scenarios of the triangle.
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Its going to have this at the end
Yes, I'm pretty sure it does, but you can't ask a geometry excercise without a diagram, or at least defining the components of the triangle with letters.
I know that but what is the answer?

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