Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120. What is the length of the third side of the triangle?

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Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120. What is the length of the third side of the triangle?

Mathematics
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help please
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Other answers:

hey m8
hmm i will try
Alright please
I am trying too...
Thank you both.
I am like stressing because of this test I cant pass
ok so you use the law of cosine i think
yea I did but I got lost after
\[c^2=a^2+b^2\]
oh i forgot the -2abcos(o)
anyways \[c^2=32^2+35^2−2(32)(35)\cos(120)\]
cos A=b^2+c^2-c^2/2ab This is the cosine formula, Isn't it? @Icedragon50
where did you get 32?
\[c^2=1024+1225-2240(-\frac{ 1 }{ 2 })=3369\]
c=\[√3369=58.04\]
and there ya go!
Thank you so much m8
np :)
g'night I'm tired xD
Same its 1 lol
bout to play league of legends

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