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anonymous

  • one year ago

Suppose a triangle has two sides of length 42 and 35, and that the angle between these two sides is 120. What is the length of the third side of the triangle?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    help please

  3. anonymous
    • one year ago
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    can you help?

  4. anonymous
    • one year ago
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    hey m8

  5. anonymous
    • one year ago
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    hmm i will try

  6. anonymous
    • one year ago
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    Alright please

  7. arindameducationusc
    • one year ago
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    I am trying too...

  8. anonymous
    • one year ago
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    Thank you both.

  9. anonymous
    • one year ago
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    I am like stressing because of this test I cant pass

  10. anonymous
    • one year ago
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    ok so you use the law of cosine i think

  11. anonymous
    • one year ago
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    yea I did but I got lost after

  12. anonymous
    • one year ago
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    \[c^2=a^2+b^2\]

  13. anonymous
    • one year ago
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    oh i forgot the -2abcos(o)

  14. anonymous
    • one year ago
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    anyways \[c^2=32^2+35^2−2(32)(35)\cos(120)\]

  15. arindameducationusc
    • one year ago
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    cos A=b^2+c^2-c^2/2ab This is the cosine formula, Isn't it? @Icedragon50

  16. anonymous
    • one year ago
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    where did you get 32?

  17. anonymous
    • one year ago
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    \[c^2=1024+1225-2240(-\frac{ 1 }{ 2 })=3369\]

  18. anonymous
    • one year ago
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    c=\[√3369=58.04\]

  19. anonymous
    • one year ago
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    and there ya go!

  20. anonymous
    • one year ago
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    @arindameducationusc ya

  21. anonymous
    • one year ago
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    Thank you so much m8

  22. anonymous
    • one year ago
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    np :)

  23. anonymous
    • one year ago
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    g'night I'm tired xD

  24. anonymous
    • one year ago
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    Same its 1 lol

  25. anonymous
    • one year ago
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    bout to play league of legends

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