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anonymous
 one year ago
Challenge! Ready? the length of the hypotenuse of a 30 degrees60 degrees90 degrees triangle is 18. What is the perimeter?
anonymous
 one year ago
Challenge! Ready? the length of the hypotenuse of a 30 degrees60 degrees90 degrees triangle is 18. What is the perimeter?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There is no diagram.

TylerD
 one year ago
Best ResponseYou've already chosen the best response.0first gotta solve for y and x

TylerD
 one year ago
Best ResponseYou've already chosen the best response.0so sin(theta)=opp/hyp which means hyp x sin(theta) = opp

TylerD
 one year ago
Best ResponseYou've already chosen the best response.0so to solve for Y, you could say 18sin(30) = Y

TylerD
 one year ago
Best ResponseYou've already chosen the best response.0to solve for X, you could say 18sin(60) = X

TylerD
 one year ago
Best ResponseYou've already chosen the best response.0then to find the perimeter, you add X + Y + 18

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0its worth remembering the ratios of the 3 sides in this particular triangle if the hypotenuse is 2 then the other sides sre dw:1438079506282:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0so to work out the smallest side 1 /2 = x / 18 solve for x

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0and for the longest leg sqrt3 / 2 = x / 18

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0so for the last one x = (sqrt3 * 18) / 2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0so can you work out the measure of the 2 legs?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0just grab a calculator and enter the numbers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Eh. I don't have one shoot.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This a challenge question anyways, okay I have the answer.
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