hwyl
  • hwyl
challenge! ready?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hwyl
  • hwyl
hwyl
  • hwyl
solve without using complement, that is \(\sf P(x) = 1 - P(x') \)
anonymous
  • anonymous
1/5?

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More answers

hwyl
  • hwyl
@UsukiDoll
anonymous
  • anonymous
Probability of at least 1 girl \[P(X \ge 1)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\]
UsukiDoll
  • UsukiDoll
I don't do stats problems.
anonymous
  • anonymous
probability of 1 girl + probability of 2 girls + probability of 3 girls + probability of 4 girls + probability of 5 girls
hwyl
  • hwyl
continue
anonymous
  • anonymous
can i do it as well
hwyl
  • hwyl
are you using \(\large \cup_{x=1} ^{n} X_i = P(x_1 \cup x_2 \cup x_3\cup x_4 \cup x_5) \)
anonymous
  • anonymous
\[P(X \ge 1)=\frac{1}{32}+\frac{1}{16}+\frac{1}{8}+\frac{1}{4}+\frac{1}{2}=\frac{1+2+4+8+16}{32}=\frac{31}{32}\] another method \[P(X=0)=\frac{1}{32}\]\[P(X \ge 1)=1-P(X=0)=1-\frac{1}{32}=\frac{32-1}{32}=\frac{31}{32}\]
hwyl
  • hwyl
haha wow
hwyl
  • hwyl
i said without using complement
anonymous
  • anonymous
I've done both with and without compliment, the compliment method is much faster anyway
Michele_Laino
  • Michele_Laino
another equivalent reasoning, can be this: the even space contains 32 possible events, nevertheless only one event, of them, is like this: BBBBB, where B stands for boy, so the total number of favorable events is 31
anonymous
  • anonymous
I think you can also do this using binomial distribution where n=5 p=q=0.5
anonymous
  • anonymous
why do u people make ur life so hard
Michele_Laino
  • Michele_Laino
oops..event space
hwyl
  • hwyl
|dw:1438078796913:dw|
hwyl
  • hwyl
|dw:1438079317682:dw|

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