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TylerD
 one year ago
@ganeshie8
TylerD
 one year ago
@ganeshie8

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TylerD
 one year ago
Best ResponseYou've already chosen the best response.1think my teacher might be wrong on something, need to check here. https://www.desmos.com/calculator/mdavtmnba2 for that graph, find the area inside the rose, but outside the circle.

TylerD
 one year ago
Best ResponseYou've already chosen the best response.1teachers solutions say just integrate (4cos(2theta))^22^2 from 0 to pi/6 then use symmetry.

TylerD
 one year ago
Best ResponseYou've already chosen the best response.1teacher used this equation here http://tutorial.math.lamar.edu/Classes/CalcII/PolarArea_files/eq0008MP.gif but im not sure if u can do that in this case?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3You want to find that area and multiply by 8 is it

TylerD
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438082672639:dw but wouldnt that integral cut off there

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Oh you're right, my bad, lets try again

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \int\limits_{0}^{\pi/4}\frac{1}{2}(4\cos2\theta)^2~d\theta\) gives below shaded area dw:1438082959464:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \int\limits_{0}^{\pi/6}\frac{1}{2}(2)^2~d\theta\) gives below shaded area dw:1438083157606:dw

TylerD
 one year ago
Best ResponseYou've already chosen the best response.1next one would be pi/6 to pi/4 for the cos(2theta)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \int\limits_{\pi/6}^{\pi/4}\frac{1}{2}(4\cos2\theta)^2~d\theta\) gives below shaded area dw:1438083357364:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3does that look okay now ? :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3lets work this and see if it matches with your teacher's answer

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3just want you notice that we're adding and subtracting that last orange piece, which is simply a waste of work... evaluate the integrals and you will see what i mean

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3your method : http://www.wolframalpha.com/input/?i=%28%5Cint%5Climits_0%5E%7B%5Cpi%2F4%7D+1%2F2%284%5Ccos%282%5Ctheta%29%29%5E2+d%5Ctheta%29++%28+%5Cint%5Climits_0%5E%7B%5Cpi%2F6%7D+1%2F2*%282%29%5E2+d%5Ctheta%29++%28%5Cint%5Climits_%7Bpi%2F6%7D%5E%7B%5Cpi%2F4%7D+1%2F2%284%5Ccos%282%5Ctheta%29%29%5E2+d%5Ctheta%29 your teacher's method : http://www.wolframalpha.com/input/?i=%28%5Cint%5Climits_0%5E%7B%5Cpi%2F6%7D+1%2F2%284%5Ccos%282%5Ctheta%29%29%5E2+d%5Ctheta%29++%28+%5Cint%5Climits_0%5E%7B%5Cpi%2F6%7D+1%2F2*%282%29%5E2+d%5Ctheta%29

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\large \int\limits_{0}^{\pi/\color{red}{6}}\frac{1}{2}(4\cos2\theta)^2~d\theta\) gives below shaded area dw:1438084278198:dw

TylerD
 one year ago
Best ResponseYou've already chosen the best response.1dang, was hoping to get extra credit for proving it wrong.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Haha! you had the right idea, pretty sure you will find other opportunities to catch ur teacher's mistakes ;)
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