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arindameducationusc
 one year ago
Challenge and also a help..... Check image for question
arindameducationusc
 one year ago
Challenge and also a help..... Check image for question

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arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1@ganeshie8 uploaded

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4look at the 10th row in pascal's triangle : dw:1438086192297:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4We want to find \(x\) such that \[\large ^{10}C_{x1}  3 *^{10}C_{x}~\gt~ 0\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes i m looking

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4dw:1438086392992:dw

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes >0 , understood that because sqare root function and denominator

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4notice that 453*10 > 0 103*1 > 0 1  3*0 > 0 so, x = 9, 10, 11 are fine

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1The answer is none of these... so I am confused

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4x = 8 doesn't work because 120  3*45 < 0 similarly x>11 doesn't work because 0  3*0 = 0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4answer is \(a\) to my knowledge

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1let me analyse once, give me some time then I may ask you if you have no problem @ganeshie8

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Is this the language for combinations? Thats interesting.... hmmm...

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1solve (10 choose (x1))  3*(10 choose x) > 0 over integers Can you explain this sentence with respect ot combination?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4\(\large ^nC_r\) is read as \(\large n~~\text{choose}~~r\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4it is called binomial coefficient and represented by symbol : \[\large \binom{n}{r}\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Each of the different groups or selections which can be made by taking some or all of a number of things(irrespective of order) //Can you please elaborate this sentence

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1// Its for Combination

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1453*10 > 0 You checked this for 9?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4yes that is for x = 9

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4suppose you went for shopping and liked 5 shirts

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4but you can only buy 3 of them

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4how many ways are there to choose 3 shirts from the 5 shirts ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4for definiteness, lets call the shirts : \(a,~b,~c,~d,~e\)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1calculations say 10

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4can you list them all ?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1ok go on... nice

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1no, I don't have that strong concept.... I would definitely understand from you.... nice....

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4no, just list them all, its a simple counting problem

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4you can buy the shirts \(a,b,c\) or \(b,c,d\) or \(c,d,e\) or ... try listing them all

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1okay ... abc acd bed bcd ade bec cde aeb

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4looks two are missing yeah

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1I am trying :P

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1no no not bae

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4``` {a,b,c} {a,b,d} {a,c,d} {b,c,d} {a,b,e} {a,c,e} {b,c,e} {a,d,e} {b,d,e} {c,d,e} ```

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4\(\large ^{5}C_3\) gives the number of ways you can choose 3 shirts from 5

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Thank you.... any method to find the terms in order... like you easily sound out the 10. suppose 16 or 24... any trick is there?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4i hope you're familiar with the formula for computing \(^5C_3\) : \[^5C_3 = \dfrac{5!}{3!(53)!} =\dfrac{5!}{3!*2!}= \dfrac{5\times 4\times 3\times 2\times 1}{3\times 2\times 1*2\times 1} = 10\]

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes yes.... ofcourse

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1I am talking about counting.. thats hard! :P

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4`Thank you.... any method to find the terms in order... like you easily sound out the 10. suppose 16 or 24... any trick is there?` hey i didnt get what you're asking..

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1suppose abcdefgh and we have to choose 3 pairs then is there any way by counting? Like suppose I want to view all possibilities

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4you want see the entire list of 56 choices ? ``` {a,b,c} {a,b,d} {a,c,d} {b,c,d} {a,b,e} {a,c,e} {b,c,e} {a,d,e} {b,d,e} {c,d,e} {a,b,f} {a,c,f} {b,c,f} {a,d,f} {b,d,f} {c,d,f} {a,e,f} {b,e,f} {c,e,f} {d,e,f} {a,b,g} {a,c,g} {b,c,g} {a,d,g} {b,d,g} {c,d,g} {a,e,g} {b,e,g} {c,e,g} {d,e,g} {a,f,g} {b,f,g} {c,f,g} {d,f,g} {e,f,g} {a,b,h} {a,c,h} {b,c,h} {a,d,h} {b,d,h} {c,d,h} {a,e,h} {b,e,h} {c,e,h} {d,e,h} {a,f,h} {b,f,h} {c,f,h} {d,f,h} {e,f,h} {a,g,h} {b,g,h} {c,g,h} {d,g,h} {e,g,h} {f,g,h} ```

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4as you can see its not so pleasant to list them all... why would you want to do that lol

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1ofcourse it is unpleasant! but Maths is Maths.... but can you tell me how did you do it?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Can Wolfram do this?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Thank you so much for giving your precious time.... :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4comb(n, set) lists all the combinations of size "n" from the set "set"

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.4but trust me, you almost never want to list all the possibilities in math most of the time you only want the total number of choices, not the list.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1ya its working.... thank you....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Ok got it! :P
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