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anonymous

  • one year ago

make a the subject of the formula s=a/4+8u will medal

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  1. anonymous
    • one year ago
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    @UsukiDoll

  2. undeadknight26
    • one year ago
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    s = a/4 + 8u Subtract both sides by 8u. s - 8u = a/4 Multiply both sides by 4. a = 4(s - 8u)

  3. UsukiDoll
    • one year ago
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    are we solving for a in this question?

  4. undeadknight26
    • one year ago
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    O.O

  5. UsukiDoll
    • one year ago
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    I just want clarification before I go further

  6. UsukiDoll
    • one year ago
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    @Sophhh786 is this question about solving for a ? as in having a by itself?

  7. anonymous
    • one year ago
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    yes

  8. UsukiDoll
    • one year ago
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    alright so given the equation \[s= \frac{a}{4}+8u\] is this your equation?

  9. anonymous
    • one year ago
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    yes

  10. UsukiDoll
    • one year ago
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    alright so.. we need to get rid of the fraction. Therefore multiply 4 throughout the equation. Can you do that?

  11. anonymous
    • one year ago
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    yes 4s =a+8u

  12. UsukiDoll
    • one year ago
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    close. the 4s and the a is right but for the 8u it should be 4(8u) = 32u

  13. anonymous
    • one year ago
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    why?

  14. UsukiDoll
    • one year ago
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    because we are multiplying 4 throughout the equation. every term is going to be multiplied by 4

  15. UsukiDoll
    • one year ago
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    \[(4)s= \frac{a(4)}{4}+8u (4)\]

  16. anonymous
    • one year ago
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    so it is like linear equations

  17. UsukiDoll
    • one year ago
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    yeah

  18. UsukiDoll
    • one year ago
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    so now we have \[4s=a+32u\] so we just need one more step. What do we need to do to get a by itself?

  19. anonymous
    • one year ago
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    divide 4 y both sides

  20. anonymous
    • one year ago
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    by

  21. UsukiDoll
    • one year ago
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    not exactly.. we need a by itself and we have this equation. it's like get all the terms that's NOT a to the left so I need to subtract both sides by 32u

  22. anonymous
    • one year ago
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    i still dont understand why we need to multiply everything by 4 in the equation u should just multiply the 4 in the fraction and s ?

  23. UsukiDoll
    • one year ago
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    we multiplied 4 throughout the equation at the beginning to get rid of the fraction

  24. UsukiDoll
    • one year ago
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    there's more than one way to solve this... first is what I and undeadknight did earlier which was to multiply 4 throughout the equation to get rid of the fraction that was attached to a. then subtract 32u on both sides. it will look something like this \[4s=a+32u \] \[4s-32u=a+32u-32u \] \[4s-32u=a \]

  25. UsukiDoll
    • one year ago
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    so let's do an alternative version where we don't multiply 4 throughout the equation first.

  26. anonymous
    • one year ago
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    ok

  27. UsukiDoll
    • one year ago
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    \[s= \frac{a}{4}+8u \] is the original equation. and we need a by itself. so I have to shift all terms (except a because we need it by itself to the right) therefore subtract 8u on both sides

  28. UsukiDoll
    • one year ago
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    \[s-8u= \frac{a}{4}\] so we have a by itself... but now we have to divide each term by 1/4

  29. anonymous
    • one year ago
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    im gonna stick with the first method you told me im gonna go through it step by step now if I have any difficulties in understanding i will give you a shout yeah? Thanks though :)

  30. UsukiDoll
    • one year ago
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    ok. :) yeah I prefer what @undeadknight26 did... for dividing 1/4 all over the equation.. we have to flip that second fraction (it will become 4/1 and then you have to use multiplication) because there's no such thing as dividing fractions.

  31. anonymous
    • one year ago
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    yeh actually @undeadknight26 version makes sense to me

  32. UsukiDoll
    • one year ago
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    and fewer steps too :)

  33. anonymous
    • one year ago
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    the only thing i dont get is why has he inserted brackets has he factorized in the last stage or something

  34. UsukiDoll
    • one year ago
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    oh ... in that step there was a 4 in common so he took it out

  35. UsukiDoll
    • one year ago
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    a=4(s-8u) distributing the 4 gives us a=4s-32u now we split up the number 32 a=4s-(4)(8)u there is a 4 on each term so we yank it out a=4(s-8u)

  36. anonymous
    • one year ago
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    could you write it like this though a=4s-32 would that be appropriate for the final answer?

  37. UsukiDoll
    • one year ago
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    yeah

  38. anonymous
    • one year ago
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    ok thanks @undeadknight26 and @UsukiDoll

  39. UsukiDoll
    • one year ago
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    you're welcome :)

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