make a the subject of the formula s=a/4+8u
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- anonymous

make a the subject of the formula s=a/4+8u
will medal

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- anonymous

@UsukiDoll

- undeadknight26

s = a/4 + 8u
Subtract both sides by 8u.
s - 8u = a/4
Multiply both sides by 4.
a = 4(s - 8u)

- UsukiDoll

are we solving for a in this question?

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## More answers

- undeadknight26

O.O

- UsukiDoll

I just want clarification before I go further

- UsukiDoll

@Sophhh786 is this question about solving for a ? as in having a by itself?

- anonymous

yes

- UsukiDoll

alright so given the equation
\[s= \frac{a}{4}+8u\]
is this your equation?

- anonymous

yes

- UsukiDoll

alright so.. we need to get rid of the fraction. Therefore multiply 4 throughout the equation. Can you do that?

- anonymous

yes 4s =a+8u

- UsukiDoll

close.
the 4s and the a is right but for the 8u
it should be 4(8u) = 32u

- anonymous

why?

- UsukiDoll

because we are multiplying 4 throughout the equation. every term is going to be multiplied by 4

- UsukiDoll

\[(4)s= \frac{a(4)}{4}+8u (4)\]

- anonymous

so it is like linear equations

- UsukiDoll

yeah

- UsukiDoll

so now we have
\[4s=a+32u\]
so we just need one more step. What do we need to do to get a by itself?

- anonymous

divide 4 y both sides

- anonymous

by

- UsukiDoll

not exactly.. we need a by itself and we have this equation. it's like get all the terms that's NOT a to the left
so I need to subtract both sides by 32u

- anonymous

i still dont understand why we need to multiply everything by 4 in the equation u should just multiply the 4 in the fraction and s ?

- UsukiDoll

we multiplied 4 throughout the equation at the beginning to get rid of the fraction

- UsukiDoll

there's more than one way to solve this... first is what I and undeadknight did earlier which was to multiply 4 throughout the equation to get rid of the fraction that was attached to a. then subtract 32u on both sides. it will look something like this
\[4s=a+32u \]
\[4s-32u=a+32u-32u \]
\[4s-32u=a \]

- UsukiDoll

so let's do an alternative version where we don't multiply 4 throughout the equation first.

- anonymous

ok

- UsukiDoll

\[s= \frac{a}{4}+8u \]
is the original equation. and we need a by itself. so I have to shift all terms (except a because we need it by itself to the right)
therefore subtract 8u on both sides

- UsukiDoll

\[s-8u= \frac{a}{4}\]
so we have a by itself... but now we have to divide each term by 1/4

- anonymous

im gonna stick with the first method you told me im gonna go through it step by step now if I have any difficulties in understanding i will give you a shout yeah? Thanks though :)

- UsukiDoll

ok. :)
yeah I prefer what @undeadknight26 did... for dividing 1/4 all over the equation.. we have to flip that second fraction (it will become 4/1 and then you have to use multiplication) because there's no such thing as dividing fractions.

- anonymous

yeh actually @undeadknight26 version makes sense to me

- UsukiDoll

and fewer steps too :)

- anonymous

the only thing i dont get is why has he inserted brackets has he factorized in the last stage or something

- UsukiDoll

oh ... in that step there was a 4 in common so he took it out

- UsukiDoll

a=4(s-8u)
distributing the 4 gives us
a=4s-32u
now we split up the number 32
a=4s-(4)(8)u
there is a 4 on each term so we yank it out
a=4(s-8u)

- anonymous

could you write it like this though a=4s-32 would that be appropriate for the final answer?

- UsukiDoll

yeah

- anonymous

ok thanks @undeadknight26 and @UsukiDoll

- UsukiDoll

you're welcome :)

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