5x + 2y = 7 y = x + 1 What is the solution set of the given system? {(5/7, 12/7)} {(12/7, 5/7)} {(9/7, 16/7)} {(16/7, 9/7)}

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5x + 2y = 7 y = x + 1 What is the solution set of the given system? {(5/7, 12/7)} {(12/7, 5/7)} {(9/7, 16/7)} {(16/7, 9/7)}

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use substitution method
U hv to put the value of y frm second equation into first equation
Ok its better you start of with substitution

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So solve 5x+2(x+1)=7
5x+2(x+1)=7 x=?
Remember Pemdas and distribute first
From there combine like terms and then solve for x
i don't know what are you guys talking about
5x+2x+2=7 Right
7x=5
divide 7 by both sides for 7x=5 then you got the x value
5x+2y=7 y=1+x Substitute the value for y in the first equation 5x+2(1+x)=7 Now Distribute and Combine like terms 5x+2x+2=7 -2 -2 7x=5 /7 /7 x=5/7 Now substitute the value of x in the any equation to find y
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agree with @carolinar7 and @arindameducationusc

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