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anonymous
 one year ago
Solve the system algebraically. Check your work.
5x + 2y = 10
3x + 2y = 6
anonymous
 one year ago
Solve the system algebraically. Check your work. 5x + 2y = 10 3x + 2y = 6

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0the y's seems to be the same so we can distribute a negative sign all over one equation and use elimination method to solve for x.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0@saseal please don't give direct answers as it's a violation of OpenStudy's Code of Conduct.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Try using matrix method. It works everytime.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Check this

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0for some reason matrix method is taught way later :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea, they are saving the best for the last lol.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0x John can find out now, what say guys?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Y is in the solution I gave, now x he can easily find out by putting in the equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[A=\left[\begin{matrix}5 & 2 \\ 3 & 2\end{matrix}\right]\] \[B = \left(\begin{matrix}x \\ y\end{matrix}\right)\] \[C = \left(\begin{matrix}10 \\ 6\end{matrix}\right)\] \[A ^{1} = \left[\begin{matrix}0.5 & 0.5 \\ 0.75 & 1.25\end{matrix}\right]\] \[A ^{1}C = B = \left[\begin{matrix}0.5 & 0.5 \\ 0.75 & 1.25\end{matrix}\right] \left(\begin{matrix}10 \\ 6\end{matrix}\right) = Find out yourself :)\]
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