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anonymous

  • one year ago

Yet another proof..

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  1. anonymous
    • one year ago
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    about?

  2. anonymous
    • one year ago
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    Okay please post the question.

  3. anonymous
    • one year ago
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  4. anonymous
    • one year ago
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    he can help you here

  5. anonymous
    • one year ago
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    I'm trying to post the options hold on haha @alexistheking777

  6. anonymous
    • one year ago
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  7. anonymous
    • one year ago
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    I don't know what he talking bout lol I don't do well in Geometry. But lemme get some people for ya. @ganeshie8 @pooja195

  8. arindameducationusc
    • one year ago
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    I got it..

  9. arindameducationusc
    • one year ago
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    It should be C.... because.....

  10. anonymous
    • one year ago
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    @arindameducationusc U r a genius

  11. arindameducationusc
    • one year ago
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    KJ, JL, and then comes angle JLK. So, Option C again....

  12. arindameducationusc
    • one year ago
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    Thank you @alexistheking777

  13. arindameducationusc
    • one year ago
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    anybody can argue.....

  14. anonymous
    • one year ago
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    Thank you @arindameducationusc this is the proof section so I am completely lost. I have so many questions

  15. anonymous
    • one year ago
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    i agree

  16. anonymous
    • one year ago
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    Since L is the midpoint of the line, ∠JLK = ∠NLM. cos(JLK) must be equal to cos(NLM).

  17. arindameducationusc
    • one year ago
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    My pleasure @jillina29 just keep asking.... :)

  18. anonymous
    • one year ago
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    So yup C

  19. anonymous
    • one year ago
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    The next one is even harder.. @arindameducationusc

  20. arindameducationusc
    • one year ago
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    please post, will definitely try my best

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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