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anonymous

  • one year ago

HELP PLEASE Solve for x: 5x2 + 25x = 0 (2 points) x = 0, x = 5 x = 0, x = -5 x = -5, x = 0, x = 5 x = 5, x = 25

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  1. arindameducationusc
    • one year ago
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    5x^2+25x=0 is this the question?

  2. anonymous
    • one year ago
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    yes

  3. arindameducationusc
    • one year ago
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    very easy.....

  4. arindameducationusc
    • one year ago
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    just take out common x

  5. arindameducationusc
    • one year ago
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    then equate x=0 and 5x+25=0

  6. arindameducationusc
    • one year ago
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    got?

  7. anonymous
    • one year ago
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    okay, o it is X=0, X=5

  8. arindameducationusc
    • one year ago
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    no x=-5

  9. anonymous
    • one year ago
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    oh okay

  10. anonymous
    • one year ago
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    is it bc we are subtracting 5?

  11. anonymous
    • one year ago
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    \[5x^2 + 25x = 0\\5x.x+5.5.x=0\\5x(x+5)=0\\ \implies\ either\ 5x=0\ or\ (x+5)=0\\ \implies\ either\ x=0\ or\ x=-5\\\]

  12. arindameducationusc
    • one year ago
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    when we shift 25 to the other side it becomes -25....

  13. anonymous
    • one year ago
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    okay

  14. arindameducationusc
    • one year ago
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    follow @eninone steps its right....

  15. arindameducationusc
    • one year ago
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    anyone you can do....

  16. anonymous
    • one year ago
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    but there is only X=5 and X=25

  17. anonymous
    • one year ago
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    never mind i know now

  18. arindameducationusc
    • one year ago
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    Ok....

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