## anonymous one year ago Help me if possible!! Solve for x: 25x2 - 36 = 0 (2 points) x = 6, 5 x = -6, -5 x = , x = - x = , x = -

1. pooja195

What are the last 2 choices?

2. anonymous

for c it is 36 over 25 and negative 36 over 25 (as in the whole equation. for d it is 6 over 5 and negative 6 over 5 (whole equation is neg)

3. anonymous

sorry it idnt come through

4. pooja195

Add 36 to both sides. $\huge~\rm~25x^2−36+36=0+36$$\huge~\rm~25x^2=36$

5. pooja195

Do you know what to do from here?

6. anonymous

do i divide??

7. anonymous

wait no

8. pooja195

yes! :D I added 36 to both sides because we are trying to ISOLATE x :) Next step is indeed to divide!

9. anonymous

oksy

10. anonymous

is the answer d?

11. pooja195

Thats correct

12. anonymous

thank you so much.

13. pooja195

You simplyfy the orginal answer which is 36/25

14. pooja195

No problem :)

15. pooja195

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16. anonymous

$25x^2 - 36 = 0\\(5x)^2-6^2=0\\(5x+6)(5x-6)=0\ [use\ a^2-b^2=(a+b+(a-b)]\\ \implies\ either\ (5x+6)=0\ or\ (5x-6)=0\\ \implies\ either\ 5x=-6\ or\ 5x=6\\ \implies\ either\ x=\frac{ -6 }{ 5 }\ or\ x=\frac{ 6 }{5 }$