anonymous
  • anonymous
Can someone help me:(? Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. -b b2 - 4ac 2a Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 4x2 + 6x + 2 = 0 (2 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
this was another one i dint quite get
pooja195
  • pooja195
The "discriminant" gives this information. It is the square root part of the quadratic formula. \[\sqrt{b^2-4ac}\]
pooja195
  • pooja195
From here solve the equation

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More answers

pooja195
  • pooja195
Start by listing your abc values a=? b=? c=?
pooja195
  • pooja195
\[\huge~\rm~ax^2+bx+c=0\]
anonymous
  • anonymous
4x^2+6x++2=0
anonymous
  • anonymous
is that how it should be set up in order
pooja195
  • pooja195
yes but we need to figure out the values using \[\huge~\rm~ax^2+bx+c=0\] That equation can you list just the NUMBERS not the signs of variables
anonymous
  • anonymous
im confused
arindameducationusc
  • arindameducationusc
@pooja195 after this, can you solve my question? http://openstudy.com/study#/updates/55b787e4e4b0f0c1f13fd1a9
pooja195
  • pooja195
Ok anything ^2 is the a value anything with an "x" is the b value anything with no varible is the c value now list the numbers :)
anonymous
  • anonymous
so b^2 is A, -b is B, and C is 2a?
pooja195
  • pooja195
wut? o-o wow you really are confused ok lets start from scratch \[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] This is the quadratic formula \[\huge~\rm~ax^2+bx+c=0\] This is standered form The discernment is The "discriminant" gives this information. It is the square root part of the quadratic formula. \[\sqrt{b^2-4ac}\] We need to solve \[\huge~\rm~4x^2 + 6x + 2 = 0\] Notice how it all matches up with the standered form equation? \[\huge~\rm~ax^2+bx+c=0\]
anonymous
  • anonymous
i know, i said that already
pooja195
  • pooja195
You have the numbers wrong a=4 b=6 c=2
anonymous
  • anonymous
oh
anonymous
  • anonymous
then why do we need just the numbers
pooja195
  • pooja195
We need just the numbers so that we can solve using the discernment
anonymous
  • anonymous
ok
arindameducationusc
  • arindameducationusc
@pooja195 I request you... okay after this
pooja195
  • pooja195
\[\sqrt{b^2-4ac}\] So now we have our abc values \[\huge~\rm~ \sqrt{6^2-4(4)(2)}\] Solve that
anonymous
  • anonymous
6^2-8 under a square root idk what
anonymous
  • anonymous
i started with parenthesis and then multiplied 4 by (8)
pooja195
  • pooja195
ok lets do this step by step whats 6^2?
anonymous
  • anonymous
36
pooja195
  • pooja195
ok leave that aside whats -4 times 4 ?
anonymous
  • anonymous
-16
pooja195
  • pooja195
Ok good -16 x 2=?
anonymous
  • anonymous
-32
pooja195
  • pooja195
good whats 36-32?
anonymous
  • anonymous
4
anonymous
  • anonymous
The 4ac
anonymous
  • anonymous
4ac decides whether you get complex number or not.
pooja195
  • pooja195
good now whats the \[\huge~\rm \sqrt4\]
anonymous
  • anonymous
2
pooja195
  • pooja195
@saseal you are confusing the asker we are already done with the problem.
anonymous
  • anonymous
oh ok
pooja195
  • pooja195
@kinserkara so whats your final answer?
anonymous
  • anonymous
sry about that
anonymous
  • anonymous
2a
pooja195
  • pooja195
its ok :) @kinserkara now 2a it would just be x=2
anonymous
  • anonymous
so the final answer is x=2
pooja195
  • pooja195
yep
anonymous
  • anonymous
ok thanks
pooja195
  • pooja195
No problem :)

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