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this was another one i dint quite get

From here solve the equation

Start by listing your abc values
a=?
b=?
c=?

\[\huge~\rm~ax^2+bx+c=0\]

4x^2+6x++2=0

is that how it should be set up in order

im confused

so b^2 is A, -b is B, and C is 2a?

i know, i said that already

You have the numbers wrong
a=4
b=6
c=2

oh

then why do we need just the numbers

We need just the numbers so that we can solve using the discernment

ok

@pooja195 I request you... okay after this

\[\sqrt{b^2-4ac}\]
So now we have our abc values
\[\huge~\rm~ \sqrt{6^2-4(4)(2)}\]
Solve that

6^2-8 under a square root idk what

i started with parenthesis and then multiplied 4 by (8)

ok lets do this step by step whats 6^2?

36

ok leave that aside whats -4 times 4 ?

-16

Ok good -16 x 2=?

-32

good whats 36-32?

The 4ac

4ac decides whether you get complex number or not.

good now whats the
\[\huge~\rm \sqrt4\]

oh ok

@kinserkara so whats your final answer?

sry about that

2a

its ok :)
@kinserkara now 2a it would just be x=2

so the final answer is x=2

yep

ok thanks

No problem :)