Can someone help me:(? Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. -b b2 - 4ac 2a Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 4x2 + 6x + 2 = 0 (2 points)

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Can someone help me:(? Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring. -b b2 - 4ac 2a Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation: 4x2 + 6x + 2 = 0 (2 points)

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this was another one i dint quite get
The "discriminant" gives this information. It is the square root part of the quadratic formula. \[\sqrt{b^2-4ac}\]
From here solve the equation

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Start by listing your abc values a=? b=? c=?
\[\huge~\rm~ax^2+bx+c=0\]
4x^2+6x++2=0
is that how it should be set up in order
yes but we need to figure out the values using \[\huge~\rm~ax^2+bx+c=0\] That equation can you list just the NUMBERS not the signs of variables
im confused
Ok anything ^2 is the a value anything with an "x" is the b value anything with no varible is the c value now list the numbers :)
so b^2 is A, -b is B, and C is 2a?
wut? o-o wow you really are confused ok lets start from scratch \[\huge~\rm~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] This is the quadratic formula \[\huge~\rm~ax^2+bx+c=0\] This is standered form The discernment is The "discriminant" gives this information. It is the square root part of the quadratic formula. \[\sqrt{b^2-4ac}\] We need to solve \[\huge~\rm~4x^2 + 6x + 2 = 0\] Notice how it all matches up with the standered form equation? \[\huge~\rm~ax^2+bx+c=0\]
i know, i said that already
You have the numbers wrong a=4 b=6 c=2
oh
then why do we need just the numbers
We need just the numbers so that we can solve using the discernment
ok
@pooja195 I request you... okay after this
\[\sqrt{b^2-4ac}\] So now we have our abc values \[\huge~\rm~ \sqrt{6^2-4(4)(2)}\] Solve that
6^2-8 under a square root idk what
i started with parenthesis and then multiplied 4 by (8)
ok lets do this step by step whats 6^2?
36
ok leave that aside whats -4 times 4 ?
-16
Ok good -16 x 2=?
-32
good whats 36-32?
4
The 4ac
4ac decides whether you get complex number or not.
good now whats the \[\huge~\rm \sqrt4\]
2
@saseal you are confusing the asker we are already done with the problem.
oh ok
@kinserkara so whats your final answer?
sry about that
2a
its ok :) @kinserkara now 2a it would just be x=2
so the final answer is x=2
yep
ok thanks
No problem :)

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