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anonymous
 one year ago
ques
anonymous
 one year ago
ques

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can we have a complex function in one variable ??? For example consider a complex variable \[z=x+jy\] What if we use x instead of y, that is the number with j we r also keeping as x \[z=x+jx\] Then a complex function in one variable may be defined \[w(z)=u(x)+j.v(x)\] Example \[\sin(z)=\sin(x+jx)=\sin(x).\cos(jx)+\cos(x).\sin(jx)\]\[\sin(z)=\sin(x).\cosh(x)+j.\cos(x).\sinh(x)\] Which is of the form \[\sin(z)=u(x)+j.v(x)\] where \[u(x)=\sin(x).\cosh(x)\]\[v(x)=\cos(x).\sinh(x)\] If I'm not wrong somewhere then why are complex functions started with 2 variables instead of taking an easier approach ??

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0don't you think the domain of function includes only the complex numbers whose real and imaginary components are equal ? this is as good as a complex valued function that takes real numbers as inputs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So this function is more like a function that only takes numbers from real domain, but by definition a complex function must take complex arguments, the thing's that confusing me is how the function is split after taking an argument, it just seems bizzare and how would you split something like \[w(z)=\sqrt{z}=\sqrt{x+jy}\] in the form of \[w(z)+u(x)+j.v(x)\] Or is it not necessary to split it into that form??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry I mean \[w(z)=u(x,y)+j.v(x,y)\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0its not necessary, how would you write some function like \(w(z) = x^2y^2 + j (x+x^3y)\) in terms of \(z\) only ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh sorry I read it wrong, the book says it's frequently express as \[w(z)=u(x,y)+j.v(x,y)\] and that's not a definition Makes sense now

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438097963551:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Isn't z a function in it's own that takes 2 reals?? So really a complex function is just a function of a function......

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0we can think of complex number as a position vector : \((x, y)\) The function machine simply maps the \(xy\) plane into \(uv\) plane dw:1438098278866:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0consider a function that takes reals and outputs reals : \(w = f(x)\) your earlier question is similar to asking : isn't \(x\) another function that takes one real ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand that but what if you can't separate your real and imaginary parts into u and v?? Like in the example \[w=f(z)=\sqrt{z}=\sqrt{x+jy}\] How is something like this mapped into the u,v plane we don't know what is \[u(x,y)\] and \[v(x,y)\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0if you want to separate real and imaginary parts then polar form should work i think but the definition of complex valued function of a complex variable doesn't require us to express the function in terms of components u(x,y) and v(x,y)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, that's what I was thinking the definition is simply of requiring z as an argument
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