Algebra!!!

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The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t2 − 0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.
[f(6)-f(2)]/(6-2)

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Other answers:

find f(6) and f(2), then plug them into the equation
You need to take the derivatives. \[f'(t) = 0.5t -5\]
Oh lord, I have no idea.
Wait, is it 2?
f(t) = 0.25t^2 − 0.5t + 3.5 f(6) = ?
Yea, I suppose.
OK.
please see the procedure of @Vocaloid
the average rate of change is like the slope of a best fit line slope of a line is change in y / corresponding change in x = y2 - y1 find the y value when x = 6 this is y2 find the y value when x = 2 this is y1 the change in x from 6 to 2 this is the same thing done above by @Vocaloid
The line isn't straight, its a quadratic curve. \[f(t) = 0.25t ^{2} + 0.5t +3.5\]
oops a typo in the function should be \[f(t) = 0.25t^2-0.5t+3.5\]
What vocaloid found was the total change during the total period from t=2 to t=6, but the question asked for average rate of change from period t=2 to t=6.
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