anonymous
  • anonymous
find the solution of this system of equation. -3x-7y=-66 and -10x-7y=-24
Mathematics
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anonymous
  • anonymous
find the solution of this system of equation. -3x-7y=-66 and -10x-7y=-24
Mathematics
chestercat
  • chestercat
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LynFran
  • LynFran
\[-3x-7y=-66\]\[-10x-7y=-24\]by elimination method, take eq2 fram eq1
LynFran
  • LynFran
\[7x=-42\]
LynFran
  • LynFran
solve for x

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anonymous
  • anonymous
\[A = \left[\begin{matrix}-3 & -7 \\ -10 & -7\end{matrix}\right]\] \[B = \left(\begin{matrix}x \\ y\end{matrix}\right)\] \[C = \left(\begin{matrix}-66 \\ -24\end{matrix}\right)\] \[A ^{-1}C = B\]
LynFran
  • LynFran
x=-42/7
anonymous
  • anonymous
Find the inverse of matrix A and multiply it with C and you get your answer.
LynFran
  • LynFran
then sub x=?? into the 1st eq. to find for y
LynFran
  • LynFran
what did u get for x @Eadorno
anonymous
  • anonymous
I got x=6 is that correct @LynFran
LynFran
  • LynFran
it shd be -6
LynFran
  • LynFran
x=-42/7 x=-6
anonymous
  • anonymous
\[|A| = (-3*-7)-(-7*-10)\]\[A ^{-1} = \frac{ 1 }{ |A| }\left[\begin{matrix}-3 & -7 \\ -10 & -7\end{matrix}\right] = \left[\begin{matrix}\frac{ 1 }{ 7 } & \frac{ -1 }{ 7 } \\ \frac{ -10 }{ 49 } & \frac{ 3 }{ 49 }\end{matrix}\right]\] \[A ^{-1}C = \left[\begin{matrix}\frac{ 1 }{ 7 } & \frac{ -1 }{ 7 } \\ \frac{ -10 }{ 49 } & \frac{ 3 }{ 49 }\end{matrix}\right]\left(\begin{matrix}-66 \\ -24\end{matrix}\right) = \left(\begin{matrix}-6 \\ 12\end{matrix}\right)\]
LynFran
  • LynFran
to find y -3(-6)-7y=-66 18-7y=-66 18+66=7y 84=7y 84/7=y 12=y i like your matrix method too @saseal
anonymous
  • anonymous
nice thank you both @saseal @LynFran
LynFran
  • LynFran
welcome
anonymous
  • anonymous
welcome
anonymous
  • anonymous
@LynFran It's my favorite method so far, works every time.

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