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anonymous
 one year ago
find the solution of this system of equation.
3x7y=66 and 10x7y=24
anonymous
 one year ago
find the solution of this system of equation. 3x7y=66 and 10x7y=24

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LynFran
 one year ago
Best ResponseYou've already chosen the best response.3\[3x7y=66\]\[10x7y=24\]by elimination method, take eq2 fram eq1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[A = \left[\begin{matrix}3 & 7 \\ 10 & 7\end{matrix}\right]\] \[B = \left(\begin{matrix}x \\ y\end{matrix}\right)\] \[C = \left(\begin{matrix}66 \\ 24\end{matrix}\right)\] \[A ^{1}C = B\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the inverse of matrix A and multiply it with C and you get your answer.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.3then sub x=?? into the 1st eq. to find for y

LynFran
 one year ago
Best ResponseYou've already chosen the best response.3what did u get for x @Eadorno

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got x=6 is that correct @LynFran

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[A = (3*7)(7*10)\]\[A ^{1} = \frac{ 1 }{ A }\left[\begin{matrix}3 & 7 \\ 10 & 7\end{matrix}\right] = \left[\begin{matrix}\frac{ 1 }{ 7 } & \frac{ 1 }{ 7 } \\ \frac{ 10 }{ 49 } & \frac{ 3 }{ 49 }\end{matrix}\right]\] \[A ^{1}C = \left[\begin{matrix}\frac{ 1 }{ 7 } & \frac{ 1 }{ 7 } \\ \frac{ 10 }{ 49 } & \frac{ 3 }{ 49 }\end{matrix}\right]\left(\begin{matrix}66 \\ 24\end{matrix}\right) = \left(\begin{matrix}6 \\ 12\end{matrix}\right)\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.3to find y 3(6)7y=66 187y=66 18+66=7y 84=7y 84/7=y 12=y i like your matrix method too @saseal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nice thank you both @saseal @LynFran

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@LynFran It's my favorite method so far, works every time.
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