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anonymous
 one year ago
please help asap.. water is being drained from a container which has the shape of an inverted right circular cone. the container has a radius of 6.00 inches at the top and a height of 10.0 inches. at the instant when the water in the container is 9.00 inches deep, the surface level is falling at a rate 1.2 inches per second. find the rate at which water is being drained from the container.
anonymous
 one year ago
please help asap.. water is being drained from a container which has the shape of an inverted right circular cone. the container has a radius of 6.00 inches at the top and a height of 10.0 inches. at the instant when the water in the container is 9.00 inches deep, the surface level is falling at a rate 1.2 inches per second. find the rate at which water is being drained from the container.

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.1use similar triangles to put the volume formula for the cone into a function of just height

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1differentiate, and solve for dV/dt

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea what im doing on this problem or what goes where?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438102666151:dw

dan815
 one year ago
Best ResponseYou've already chosen the best response.0Do you know the formula for the volume of a cone as a function of its height V=f(h)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1solve for r, and put that into the volume formula so it is just in terms of h.

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1Givens  h=9, dh/dt = 1.2

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0and I saw this dw:1438103242401:dw

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1\[V = \frac{ 1 }{ 3 }\pi*r^2*h\] from similar triangles... \[r = \frac{ 3 }{ 5 }h\] \[V(h) = \frac{ 1 }{ 3 }\pi*(\frac{ 3 }{ 5 }h)^2*h\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1simplify that, then differentiate both sides w.r.t time, you are given dh/dt

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1\[V = \frac{ 3 }{ 25 }\pi*h^3\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1chain rule \[\frac{ dV }{ dt }=[\frac{ 3 }{ 25 }\pi]*3h^2*\frac{ dh }{ dt }\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.1you are given h and dh/dt, find dV/dt
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