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anonymous
 one year ago
Hey just wanting to know how you can find a parabola given the focal and directrix
anonymous
 one year ago
Hey just wanting to know how you can find a parabola given the focal and directrix

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Meant the equation of a parabola

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry i don't know the question but i just wanted to say Battle Field Friends

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The vertex is half way between the Focal and the directrix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I know and so then I just plug in the numbers then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0parabola takes the from of \( y^2 = 4ax \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then how would I solve it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The distance between directix and focus is 2p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will step out and let saseal take over so you do not get confused.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because I need to know how to find the equation first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because I need to know how to find the equation first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you take the midpoint between focus and directix \[(\frac{ x _{2}x _{1} }{ 2 })\] change it to y if your parabola opens the other side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yup that distance is your p and you plug it into the formula
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