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anonymous

  • one year ago

Hey just wanting to know how you can find a parabola given the focal and directrix

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  1. anonymous
    • one year ago
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    Meant the equation of a parabola

  2. anonymous
    • one year ago
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    Sorry i don't know the question but i just wanted to say Battle Field Friends

  3. anonymous
    • one year ago
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    The vertex is half way between the Focal and the directrix

  4. anonymous
    • one year ago
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    \[y^2=4px\]

  5. anonymous
    • one year ago
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    Yes I know and so then I just plug in the numbers then?

  6. anonymous
    • one year ago
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    parabola takes the from of \( y^2 = 4ax \)

  7. anonymous
    • one year ago
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    So then how would I solve it?

  8. anonymous
    • one year ago
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    The distance between directix and focus is 2p

  9. anonymous
    • one year ago
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    I will step out and let saseal take over so you do not get confused.

  10. anonymous
    • one year ago
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    Because I need to know how to find the equation first

  11. anonymous
    • one year ago
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    Because I need to know how to find the equation first

  12. anonymous
    • one year ago
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    distance equation?

  13. anonymous
    • one year ago
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    Yes but is that it?

  14. anonymous
    • one year ago
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    Yes but is that it?

  15. anonymous
    • one year ago
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    you take the midpoint between focus and directix \[(\frac{ x _{2}-x _{1} }{ 2 })\] change it to y if your parabola opens the other side

  16. anonymous
    • one year ago
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    yup that distance is your p and you plug it into the formula

  17. anonymous
    • one year ago
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    Soo is that it?

  18. anonymous
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    Alright thank you!

  20. anonymous
    • one year ago
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    welcome

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spraguer (Moderator)
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