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anonymous
 one year ago
what are the equations to these diagrams? (attachment) please help will medal!!
anonymous
 one year ago
what are the equations to these diagrams? (attachment) please help will medal!!

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.0the first one is a quadratic equation with a negative coefficient of x^2. It has zeros of 2 and 8. and a vertex at (3,6) can you find the equation from this info?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the 1st diagram \[(x+3)^2=4(y6)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is this right? −(x+3)2=4(y−6) @welshfella

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the ellipse equation is \[\frac{ (y4)^2 }{ 6^2 }+\frac{ (x3)^2 }{ 4^2 }=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the first one? @saseal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes the first picture

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about the second? @saseal

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0yes that is correct for the first graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im doing the circle now, its \[(x+6)^2+(y+2)^2=5^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about #13 and #14? then i will figure out the rest myself thank you for all ur help @saseal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (x7)^2 }{ 2^2 }\frac{ y2)^2 }{ 2^2}=1\] for the hyperbola

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0circle is #13 and hyperbola is #14

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about the one on the top right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First oval is \[\frac{ (x7)^2 }{ 6^2 }+\frac{ y^2 }{ 3^2 }=1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if i tag you in some other ones on a different question could you help?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0plz dont just give answers saseal Code of Conduct asks us to Guide the user to the answers

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I can't give ya answer now, work the last one out yourself; parabola equation for that curve looks something like this :) \[(y+1)^2=4p(x4)^2\]
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