## anonymous one year ago what are the equations to these diagrams? (attachment) please help will medal!!

1. anonymous

2. anonymous

3. anonymous

4. welshfella

the first one is a quadratic equation with a negative coefficient of x^2. It has zeros of 2 and -8. and a vertex at (-3,6) can you find the equation from this info?

5. anonymous

For the 1st diagram $-(x+3)^2=4(y-6)$

6. anonymous

is this right? −(x+3)2=4(y−6) @welshfella

7. anonymous

the ellipse equation is $\frac{ (y-4)^2 }{ 6^2 }+\frac{ (x-3)^2 }{ 4^2 }=1$

8. anonymous

for the first one? @saseal

9. anonymous

yes the first picture

10. anonymous

11. welshfella

yes that is correct for the first graph

12. anonymous

im doing the circle now, its $(x+6)^2+(y+2)^2=5^2$

13. anonymous

what about #13 and #14? then i will figure out the rest myself thank you for all ur help @saseal

14. anonymous

$\frac{ (x-7)^2 }{ 2^2 }-\frac{ y-2)^2 }{ 2^2}=1$ for the hyperbola

15. anonymous

circle is #13 and hyperbola is #14

16. anonymous

what about the one on the top right?

17. anonymous

the oval @saseal

18. anonymous

2nd picture?

19. anonymous

yes

20. anonymous

gimme a few minutes

21. anonymous

thank you so much

22. anonymous

First oval is $\frac{ (x-7)^2 }{ 6^2 }+\frac{ y^2 }{ 3^2 }=1$

23. anonymous

if i tag you in some other ones on a different question could you help?

24. welshfella

plz dont just give answers saseal Code of Conduct asks us to Guide the user to the answers

25. anonymous

okies

26. anonymous

so I can't give ya answer now, work the last one out yourself; parabola equation for that curve looks something like this :) $(y+1)^2=4p(x-4)^2$