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## ashking1 one year ago Find (f + g)(x).

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1. ashking1

$g= \sqrt{6x-9}$

2. ashking1

f=$\sqrt{6x+9}$

3. anonymous

$(f+g)(x)=f(x)+g(x)$ Use this formula, everything else is given

4. anonymous

what subject is this for?

5. ashking1

precal i think i got it is the answer 6x

6. anonymous

I believe so.

7. ashking1

can you help me with one more

8. anonymous

sure

9. ashking1

Determine algebraically whether the function is even, odd, or neither even nor odd. f(x)= x+ 4/x

10. anonymous

what are the answer options just want to check

11. ashking1

even odd or neither

12. anonymous

f(x)= x+4/x in my opinion would be odd mainly because its the opposite of the 4/x

13. anonymous

excuse me if im wrong i havent been studying this

14. freckles

(f+g)(x)=f(x)+g(x) don't know how you got 6x if really is that $f(x)=\sqrt{6x+9} \text{ and } g(x)=\sqrt{6x-9}$

15. freckles

just replace f(x) with sqrt(6x+9) and replace g(x) with sqrt(6x-9)

16. freckles

also to determine if a function is odd or even (or neither odd or even) the first step is to plug in -x

17. freckles

if you receive f(-x)=f(x), then f is even if you receive f(-x)=-f(x), then f is odd

18. ashking1

so it would be odd am i correct

19. freckles

$f(x)=x+\frac{4}{x} \\ \text{ plug \in } -x \\ f(-x)=-x+\frac{4}{-x} \\ f(-x)=-(x+\frac{4}{x}) \\ f(-x)=-f(x) \\ \text{ yep } f \text{ is odd } \\ \text{ unless you meant } f(x)=\frac{x+4}{x} \\ \text{ then the story is a bit different }$

20. freckles

you would still plug in -x of course

21. anonymous

yes

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