ashking1
  • ashking1
Find (f + g)(x).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ashking1
  • ashking1
\[ g= \sqrt{6x-9} \]
ashking1
  • ashking1
f=\[\sqrt{6x+9}\]
anonymous
  • anonymous
\[(f+g)(x)=f(x)+g(x)\] Use this formula, everything else is given

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More answers

anonymous
  • anonymous
what subject is this for?
ashking1
  • ashking1
precal i think i got it is the answer 6x
anonymous
  • anonymous
I believe so.
ashking1
  • ashking1
can you help me with one more
anonymous
  • anonymous
sure
ashking1
  • ashking1
Determine algebraically whether the function is even, odd, or neither even nor odd. f(x)= x+ 4/x
anonymous
  • anonymous
what are the answer options just want to check
ashking1
  • ashking1
even odd or neither
anonymous
  • anonymous
f(x)= x+4/x in my opinion would be odd mainly because its the opposite of the 4/x
anonymous
  • anonymous
excuse me if im wrong i havent been studying this
freckles
  • freckles
(f+g)(x)=f(x)+g(x) don't know how you got 6x if really is that \[f(x)=\sqrt{6x+9} \text{ and } g(x)=\sqrt{6x-9}\]
freckles
  • freckles
just replace f(x) with sqrt(6x+9) and replace g(x) with sqrt(6x-9)
freckles
  • freckles
also to determine if a function is odd or even (or neither odd or even) the first step is to plug in -x
freckles
  • freckles
if you receive f(-x)=f(x), then f is even if you receive f(-x)=-f(x), then f is odd
ashking1
  • ashking1
so it would be odd am i correct
freckles
  • freckles
\[f(x)=x+\frac{4}{x} \\ \text{ plug \in } -x \\ f(-x)=-x+\frac{4}{-x} \\ f(-x)=-(x+\frac{4}{x}) \\ f(-x)=-f(x) \\ \text{ yep } f \text{ is odd } \\ \text{ unless you meant } f(x)=\frac{x+4}{x} \\ \text{ then the story is a bit different }\]
freckles
  • freckles
you would still plug in -x of course
anonymous
  • anonymous
yes

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