anonymous
  • anonymous
Find cot θ if csc=\frac{ sqrt{17} }{ 4 } and tan θ>0.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\csc=\frac{ \sqrt{17} }{ 4 }\]
anonymous
  • anonymous
I know that I will use Pythagorean theorem, but I'm kinda stuck with it.
Lurker
  • Lurker
|dw:1438106224288:dw|

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ali2x2
  • ali2x2
cscθ=17−−√4→1sinθ=17−−√4→sinθ=417−−√
Lurker
  • Lurker
|dw:1438106306044:dw|
ali2x2
  • ali2x2
cotθ=adjacentopposite
anonymous
  • anonymous
|dw:1438106352863:dw|
Lurker
  • Lurker
|dw:1438106355892:dw|
Lurker
  • Lurker
Can you work it out from here
anonymous
  • anonymous
|dw:1438106405102:dw|
ali2x2
  • ali2x2
|dw:1438106432034:dw|
anonymous
  • anonymous
How come it became 1?
Lurker
  • Lurker
Pythagorean theorem
anonymous
  • anonymous
Yes, but with what I drew above, is that the correct way to solve it?
Lurker
  • Lurker
yes
ali2x2
  • ali2x2
the answer is 1/4
Lurker
  • Lurker
|dw:1438106617092:dw|
ali2x2
  • ali2x2
.-.
ali2x2
  • ali2x2
is that one of your choices
Lurker
  • Lurker
ali2x2 please let her work it out
ali2x2
  • ali2x2
ok sorry....
anonymous
  • anonymous
Lol I just wanna know how to get the other side and I'm good. :)
ali2x2
  • ali2x2
ok look
ali2x2
  • ali2x2
brb
anonymous
  • anonymous
the cot is 1/4.
ali2x2
  • ali2x2
back
Lurker
  • Lurker
|dw:1438106693095:dw|
ali2x2
  • ali2x2
use this you guys
ali2x2
  • ali2x2
did some research
Lurker
  • Lurker
|dw:1438106711345:dw|
ali2x2
  • ali2x2
they explained it better than me xD
ali2x2
  • ali2x2
yes
ali2x2
  • ali2x2
its 1
anonymous
  • anonymous
Wooow the amount of radical signs kind of overwhelmed me, that's why I didn't get it lol. But am I correct with my answer?
ali2x2
  • ali2x2
sort of
ali2x2
  • ali2x2
ey math
anonymous
  • anonymous
did you see my answer? lol is it 1/4?
ali2x2
  • ali2x2
yes thats what ive been saying ._.
anonymous
  • anonymous
because you said sort of, so i was confused.
anonymous
  • anonymous
but anyway thanks for the help!
ali2x2
  • ali2x2
yeah i didnt explain it well
ali2x2
  • ali2x2
no prob

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