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anonymous

  • one year ago

Will Fan For Great Help!! The legs of a right triangle are 6 units and 7 units. What is the length of the hypotenuse? square root 13 units 13 units square root 85 units 85 units

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  1. anonymous
    • one year ago
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    @Skielerlucas04

  2. Vocaloid
    • one year ago
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    (leg)^2 + (leg)^2 = hypotenuse^2

  3. anonymous
    • one year ago
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    mmmhmmm

  4. Vocaloid
    • one year ago
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    plug in 6 and 7 for the legs

  5. anonymous
    • one year ago
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    im not very good with hypotentnuse

  6. Vocaloid
    • one year ago
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    leg 1 = 6 leg 2 = 7 (leg 1)^2 + (leg 2)^2 = ?

  7. anonymous
    • one year ago
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    ok

  8. anonymous
    • one year ago
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    now square root that answer

  9. anonymous
    • one year ago
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    |dw:1438106956180:dw|

  10. Vocaloid
    • one year ago
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    uh, let's take it one step at a time leg 1 = 6 (leg 1)^2 = ?

  11. anonymous
    • one year ago
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    7

  12. Vocaloid
    • one year ago
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    leg 1 = 6 (leg 1)^2 = (leg 1)*(leg 1) = ?

  13. anonymous
    • one year ago
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    ooppps

  14. anonymous
    • one year ago
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    noooo wait sory

  15. anonymous
    • one year ago
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    1

  16. anonymous
    • one year ago
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    what is 6 squared?

  17. anonymous
    • one year ago
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    3

  18. Vocaloid
    • one year ago
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    "squared" means multiply by itself what is 6 squared = 6*6 = ?

  19. anonymous
    • one year ago
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    36

  20. anonymous
    • one year ago
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    good! now 7*7

  21. anonymous
    • one year ago
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    42

  22. anonymous
    • one year ago
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    no 49

  23. anonymous
    • one year ago
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    sorry

  24. anonymous
    • one year ago
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    good, so add those up

  25. anonymous
    • one year ago
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    49+36=85

  26. anonymous
    • one year ago
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    okay so now to get a hypotenuse you would square that. but since it isn't a perfect square you'll just leave it as 'the square root of 85'

  27. anonymous
    • one year ago
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    did that help?

  28. anonymous
    • one year ago
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    yesh please help me with more

  29. anonymous
    • one year ago
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    okay, close this question and open another. tag me in it if you need :)

  30. anonymous
    • one year ago
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    k

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