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anonymous
 one year ago
6th term of expansion (1+x)^32
quickest method
anonymous
 one year ago
6th term of expansion (1+x)^32 quickest method

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1for a binomial \[(1+ x)^n = \sum_{r = 0}^{n}\left(\begin{matrix}n \\ r\end{matrix}\right) 1^{n  r}x^r\] so to find the 6th term let r = 5 remember the terms start at r = 0 0, 1, 2, 3, 4, 5 and evaluate \[\left(\begin{matrix}32 \\ 5\end{matrix}\right) 1^{325}\times x^5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And what if the terms were (a+b) instead of (1+x)
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