The numbers 1 through 5 are recorded on individual slips of paper and placed in a hat. What is the probability of drawing the 3, not replacing it, and then drawing the 4?

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The numbers 1 through 5 are recorded on individual slips of paper and placed in a hat. What is the probability of drawing the 3, not replacing it, and then drawing the 4?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ok The odd of picking a 3 would be 1 in 5 and after that, the odds of picking a 4 would be 1 in 4...so the combined odds would be: 1over5∗1over4=?
probability of drawing the 3 is 1/5
and the probability of drawing a 4 after that would be 1/4, since the person took out the possibility for drawing a 3, again
so 1/4
is it 1/20
yes
1/25 1/20 1/9 9/20
1/20 is correct
do you remember what I said about multiplying the independent events to get the probability of the compound event? If you did, good job

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