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anonymous
 one year ago
Verify the identity.
quantity one minus sine of x divided by cosine of x equals cosine of x divided by quantity one plus sine of x
anonymous
 one year ago
Verify the identity. quantity one minus sine of x divided by cosine of x equals cosine of x divided by quantity one plus sine of x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks like this \[\frac{ 1  sinx }{ cosx } = \frac{ cosx }{ 1 + sinx }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0or i would solve right to make it equal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. so how would I start with right side?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0you need to multiply denominator and numerator by the conjugate of 1+sinx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it is \[\frac{ cosx  sinxcosx }{ 1\sin^2x}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0okay so you don't need to distribute 1sinx by cosx at the numerator \[\frac{ \cos(x)(1\sin(x)) }{ 1\sin^2 }\] apply the identity 1sin^2x equal to what ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be \[\frac{ cosx(1sinx) }{ \cos^2x }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right cos^2x can be written as cos x times cos x \[\huge\rm \frac{ \cos(x)(1\sin(x)) }{ cos(x) \times cos(x) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so factor out top and bottom leaves me with \[\frac{ 1sinx }{ cosx }\]
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