anonymous
  • anonymous
Medal A physician orders enoxaparin for a patient with deep vein thrombosis. The in stock solution of enoxaparin is 300 mg / 3 mL and the dosage instructions are 1 mg/kg SC q.12.h., and the patient weighs 85kg. Provide complete, detailed instructions for proper drug administration
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Lurker
  • Lurker
1 mg/kg a patient weighs 85 kg therefore he needs 85 mg
Lurker
  • Lurker
the solution you are giving him has 300 mg / 3 mL
Lurker
  • Lurker
how many mL do you have to give him for 85 mg then

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anonymous
  • anonymous
8.5 mL
Lurker
  • Lurker
no no, are you confused with anything i ve typed so far
anonymous
  • anonymous
m not confused i just dont understand the 85 mg in mL how do you convert this
Lurker
  • Lurker
okays the solution you administer to the patient has 300 mg for every 3 mL
Lurker
  • Lurker
you have to give him x mL such that he only get 85 mg
Lurker
  • Lurker
you can look at the ratios there 300 mg for 3 mL means 100 mg for 1 mL
Lurker
  • Lurker
which is not low enough, can you think of how to get it to 85 mg for some other mL
anonymous
  • anonymous
ok so we need to make 85mg to mL right
Lurker
  • Lurker
we arent turning mg to ml we are just trying to figure out the ratios here
anonymous
  • anonymous
ohh i c
Lurker
  • Lurker
for example what we did in that middle step there how i got 100 mg for 1 ml is since 300/3 = 100/1 this is the same ratio in the same way 300/3=85/x what should x be to maintain the same ratio
anonymous
  • anonymous
so we cross multiply to get it right
Lurker
  • Lurker
yep
Lurker
  • Lurker
solve for x
Lurker
  • Lurker
|dw:1438112286446:dw|
Lurker
  • Lurker
you see how 1*100 =100 for the 100/1 case then 85/x x*100=85 so x=0.85
Lurker
  • Lurker
|dw:1438112353485:dw|
Lurker
  • Lurker
85 mg for 0.85 mL so you need to give the patient 0.85 mL of solution
anonymous
  • anonymous
so the answer is 0.85mL?
Lurker
  • Lurker
yeah
anonymous
  • anonymous
thank you :)
Lurker
  • Lurker
welcome

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