A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Rewrite with only sin x and cos x.
sin 2x  cos 2x
anonymous
 one year ago
Rewrite with only sin x and cos x. sin 2x  cos 2x

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is so confusing because I know that what I did was correct, but my answer is not one of the choices.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1well what do you know about sin(2x) and cos(2x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I kind of made the choices as the guide, so here's what I did.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin2x\cos2x\] \[2 \sin x \cos x(12\sin^2x)\] \[2 \sin x \cos x 1+2\sin^2x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here are the choices btw. a.2 sinx cosx  1 + 2 sin2x b. 2 sin x cos2x  1 + 2 sin2x c. 2 sin x cos2x  sin x + 1  2 sin2x d. 2 sin x cos2x  1  2 sin2x And my answer is A.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1that works.... so looking at the answer options they have used cos(2x) = 1  2 sin^2(x) so as you have posted 2sin(x)cos(x)  (1  2sin^2(x)) = 2 sin(x)cos(x) 1+ 2sin^2(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that sin^2x = 2 sin x cos x cos 2x = 12sin^2x = 2 cos^2x1 =cos^2xsin^2x

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1you have the correct solution

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1yes \[2\sin(x)\cos(x)  1 + 2 \sin^2(x)\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.