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anonymous
 one year ago
Which of the following statements describes one part of completing the square for x^2 + 4x = 32?
a. Take the square root of 36 and add 2.
b. Take the square root of 32 and subtract 2.
c. Take the square root of 36 and subtract 2.
anonymous
 one year ago
Which of the following statements describes one part of completing the square for x^2 + 4x = 32? a. Take the square root of 36 and add 2. b. Take the square root of 32 and subtract 2. c. Take the square root of 36 and subtract 2.

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campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1the answers relate to the solution to the equation by using the complete the square method so you need to have completed the square to start the process of solving so to make the left hand side a perfect square what needs to be added...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0four needs to be added

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1great so the equation becomes \[x^2 + 4x + 4 =32 + 4 ~~~~or~~~~~(x + 2)^2 = 36\] so you are being asked, if you have the new equation above, what steps d you need to take to solve for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to apply the square root property and solve for x so that makes the equation turn into \[x+2=\pm \sqrt{36}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So would the answer be a. Take the square root of 36 and add 2.? because at one point I subtract minus two (making it plus?) from the square root of 36 (6)

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1that's correct so the 2 steps are 1. square root both sides 2. subtract 2 so just match that to the answer choices

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1I think its option C you took the square root of 36 then subtracted 2 from both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh ok I get it thanks for the help
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