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anonymous

  • one year ago

A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations.

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  1. anonymous
    • one year ago
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    @campbell_st

  2. anonymous
    • one year ago
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    I only need help with part B

  3. campbell_st
    • one year ago
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    ok... so what solution did you get..?

  4. anonymous
    • one year ago
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    for part A?

  5. anonymous
    • one year ago
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    @campbell_st

  6. campbell_st
    • one year ago
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    yes can you post the solution to part A

  7. anonymous
    • one year ago
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    -6x+14y=-32 I got this I multiplied first equation by 2

  8. campbell_st
    • one year ago
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    ok.... this is what I would have done I would multiply every term in the 1st equation by -3. this would allow you to eliminate x equation 2 doesn't change 9x - 21y = 48 -9x +5y = 16 add the 2 equations --------------- -16y = 64 so y = -4 substitute this into either of the original equations to find x. does that make sense...?

  9. anonymous
    • one year ago
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    yes thanks you soo much

  10. campbell_st
    • one year ago
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    ok... so when you get the solution part B seems to be asking you to substitute the values into 9x - 21y = 48 to show the solution is correct

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