HelloKitty17
  • HelloKitty17
An expression is shown below: 3x3y + 12xy - 9x2y - 36y Part A: Rewrite the expression so that the GCF is factored completely. Show the steps of your work. (3 points) Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points) Part C: If the two middle terms were switched so that the expression became 3x3y - 9x2y + 12xy - 36y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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HelloKitty17
  • HelloKitty17
Help plz
HelloKitty17
  • HelloKitty17
@madison.bush
HelloKitty17
  • HelloKitty17
hey

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More answers

OregonDuck
  • OregonDuck
Part A: \[3y(x ^{3}+4x-3x ^{2}-12)\] Part B: \[3y(x ^{2}+4)(x-3)\]
OregonDuck
  • OregonDuck
help with part c plz
HelloKitty17
  • HelloKitty17
@katt9421
HelloKitty17
  • HelloKitty17
Could you help with part c
welshfella
  • welshfella
the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression
welshfella
  • welshfella
if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.
OregonDuck
  • OregonDuck
Part c: the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression.if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.
OregonDuck
  • OregonDuck
Part A: Part A: 3x^3y+12xy−9x^2y−36y GCF of numbers = 3 GCF of y terms = y 3x^3y+12xy−9x^2y−36y after factoring the 3 : 3(x^3y+4xy−3x^2y−12y) after factoring the y : 3y(x^3+4x−3x^2−12) Answer: 3y(x^3+4x−3x^2−12)
OregonDuck
  • OregonDuck
Part B: 3y(x^3+4x−3x^2−12) Factoring out GCF from first two terms gives : 3y(x(x^2+4)−3x^2−12) 3y(x^3+4x−3x^2−12) Factoring out GCF from first two terms gives : 3y(x(x^2+4)−3x^2−12) Factoring the GCF from last two terms gives : 3y(x(x^2+4)−3(x^2+4)) factoring out the (x^2+4) from the terms inside parenthesis gives : 3y(x^2+4)(x−3)

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