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HelloKitty17

  • one year ago

An expression is shown below: 3x3y + 12xy - 9x2y - 36y Part A: Rewrite the expression so that the GCF is factored completely. Show the steps of your work. (3 points) Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points) Part C: If the two middle terms were switched so that the expression became 3x3y - 9x2y + 12xy - 36y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)

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  1. HelloKitty17
    • one year ago
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    Help plz

  2. HelloKitty17
    • one year ago
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    @madison.bush

  3. HelloKitty17
    • one year ago
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    hey

  4. OregonDuck
    • one year ago
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    Part A: \[3y(x ^{3}+4x-3x ^{2}-12)\] Part B: \[3y(x ^{2}+4)(x-3)\]

  5. OregonDuck
    • one year ago
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    help with part c plz

  6. HelloKitty17
    • one year ago
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    @katt9421

  7. HelloKitty17
    • one year ago
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    Could you help with part c

  8. welshfella
    • one year ago
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    the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression

  9. welshfella
    • one year ago
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    if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.

  10. OregonDuck
    • one year ago
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    Part c: the factored expression will still be equivalent to the answer in B. Moving the middle 2 terms makes no difference to the expression.if you plugged in say x=1 and y=2 into the 2 expression the result will be the same for both. Expressions may be written in different ways.

  11. OregonDuck
    • one year ago
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    Part A: Part A: 3x^3y+12xy−9x^2y−36y GCF of numbers = 3 GCF of y terms = y 3x^3y+12xy−9x^2y−36y after factoring the 3 : 3(x^3y+4xy−3x^2y−12y) after factoring the y : 3y(x^3+4x−3x^2−12) Answer: 3y(x^3+4x−3x^2−12)

  12. OregonDuck
    • one year ago
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    Part B: 3y(x^3+4x−3x^2−12) Factoring out GCF from first two terms gives : 3y(x(x^2+4)−3x^2−12) 3y(x^3+4x−3x^2−12) Factoring out GCF from first two terms gives : 3y(x(x^2+4)−3x^2−12) Factoring the GCF from last two terms gives : 3y(x(x^2+4)−3(x^2+4)) factoring out the (x^2+4) from the terms inside parenthesis gives : 3y(x^2+4)(x−3)

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