anonymous
  • anonymous
Simplify square root of 2 multiplied by the cube root of 2.
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt{2}*\sqrt[3]{2}\]
anonymous
  • anonymous
Is it like that?
anonymous
  • anonymous
Change each radical to rational expression. \[\sqrt{2}-->2^{\frac{ 1 }{ 2 }}\] \[\sqrt[3]{2}-->2^\frac{ 1 }{ 3 }\] Then use LCD in both fractions.

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More answers

anonymous
  • anonymous
i have no idea how to do it. I think its 2 2/3
anonymous
  • anonymous
and yes it looks like that
anonymous
  • anonymous
What is the least common multiple of 2 and 3?
anonymous
  • anonymous
2: 2, 4, 6, 8, 10 3: 3, 6, 9, 12, 15
anonymous
  • anonymous
6?
anonymous
  • anonymous
Yes! So, |dw:1438119775405:dw|
anonymous
  • anonymous
What is \[6\div2?\]
anonymous
  • anonymous
3
anonymous
  • anonymous
Good! Than multiply 3 to the numerator.|dw:1438119897874:dw|
anonymous
  • anonymous
Hello?
anonymous
  • anonymous
What is 3 x 1?
anonymous
  • anonymous
3
anonymous
  • anonymous
sorry lost connection
anonymous
  • anonymous
Now do it to the other one. |dw:1438120062129:dw|
anonymous
  • anonymous
What is 6/3?
anonymous
  • anonymous
2
anonymous
  • anonymous
Then multiply it by the numerator of 1/3.
anonymous
  • anonymous
What is the answer?
anonymous
  • anonymous
6? soo 2 1/6
anonymous
  • anonymous
What is 2 times 1?
anonymous
  • anonymous
2
anonymous
  • anonymous
|dw:1438120283484:dw|
anonymous
  • anonymous
|dw:1438120302016:dw|
anonymous
  • anonymous
What is 3+2?
anonymous
  • anonymous
2 5/6
anonymous
  • anonymous
Yes. Do you want to turn it into radical?
anonymous
  • anonymous
no thankyou it doesnt ask to do that.
anonymous
  • anonymous
thankyou for helping me understand!
anonymous
  • anonymous
Okay! You're welcome. :)

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