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anonymous

  • one year ago

Simplify square root of 2 multiplied by the cube root of 2.

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  1. anonymous
    • one year ago
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    \[\sqrt{2}*\sqrt[3]{2}\]

  2. anonymous
    • one year ago
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    Is it like that?

  3. anonymous
    • one year ago
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    Change each radical to rational expression. \[\sqrt{2}-->2^{\frac{ 1 }{ 2 }}\] \[\sqrt[3]{2}-->2^\frac{ 1 }{ 3 }\] Then use LCD in both fractions.

  4. anonymous
    • one year ago
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    i have no idea how to do it. I think its 2 2/3

  5. anonymous
    • one year ago
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    and yes it looks like that

  6. anonymous
    • one year ago
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    What is the least common multiple of 2 and 3?

  7. anonymous
    • one year ago
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    2: 2, 4, 6, 8, 10 3: 3, 6, 9, 12, 15

  8. anonymous
    • one year ago
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    6?

  9. anonymous
    • one year ago
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    Yes! So, |dw:1438119775405:dw|

  10. anonymous
    • one year ago
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    What is \[6\div2?\]

  11. anonymous
    • one year ago
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    3

  12. anonymous
    • one year ago
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    Good! Than multiply 3 to the numerator.|dw:1438119897874:dw|

  13. anonymous
    • one year ago
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    Hello?

  14. anonymous
    • one year ago
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    What is 3 x 1?

  15. anonymous
    • one year ago
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    3

  16. anonymous
    • one year ago
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    sorry lost connection

  17. anonymous
    • one year ago
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    Now do it to the other one. |dw:1438120062129:dw|

  18. anonymous
    • one year ago
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    What is 6/3?

  19. anonymous
    • one year ago
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    2

  20. anonymous
    • one year ago
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    Then multiply it by the numerator of 1/3.

  21. anonymous
    • one year ago
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    What is the answer?

  22. anonymous
    • one year ago
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    6? soo 2 1/6

  23. anonymous
    • one year ago
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    What is 2 times 1?

  24. anonymous
    • one year ago
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    2

  25. anonymous
    • one year ago
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    |dw:1438120283484:dw|

  26. anonymous
    • one year ago
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    |dw:1438120302016:dw|

  27. anonymous
    • one year ago
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    What is 3+2?

  28. anonymous
    • one year ago
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    2 5/6

  29. anonymous
    • one year ago
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    Yes. Do you want to turn it into radical?

  30. anonymous
    • one year ago
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    no thankyou it doesnt ask to do that.

  31. anonymous
    • one year ago
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    thankyou for helping me understand!

  32. anonymous
    • one year ago
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    Okay! You're welcome. :)

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