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anonymous

  • one year ago

  Which two expressions are equivalent? A. 4.3(14x+2.5) B. 14(4.3x+2.5) C. 20.6x+28+39.6x+7 D. 60.2x+2.5 Medal and fan for best answer. I am not good at figuring out equivalent expressions.

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  1. mathstudent55
    • one year ago
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    You need to use the distributive property in each choice A and B. Combine like terms in choice C. Then compare all results including choice D.

  2. mathstudent55
    • one year ago
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    Recall the distributive property: a(b + c) = ab + ac Example: 5(2x + 4) = 5 * 2x + 5 * 4 = 10x + 20

  3. mathstudent55
    • one year ago
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    Can you do the distributive property on choice A? What do you get? A. 4.3(14x+2.5)

  4. anonymous
    • one year ago
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    Ok so I have 4.3*2.5, but i'm having trouble multiplying 4.3 *14x. I can't seem to figure out how to multiply with the variable number multiplication thingy.

  5. anonymous
    • one year ago
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    @mathstudent55

  6. anonymous
    • one year ago
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    @carolinar7

  7. anonymous
    • one year ago
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    @sweetburger @Elsa213 @YanaSidlinskiy @misssunshinexxoxo

  8. anonymous
    • one year ago
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    Anyone? I would like help plz. My schoolwork is taken me all day and I wanna b done with it.

  9. jim_thompson5910
    • one year ago
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    to multiply 4.3 *14x, you drop the x for now and just evaluate 4.3 *14 you then tack on x to the answer

  10. jim_thompson5910
    • one year ago
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    example: 2*8x = 16x because 2*8 = 16

  11. anonymous
    • one year ago
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    ty!

  12. jim_thompson5910
    • one year ago
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    sure thing

  13. mathstudent55
    • one year ago
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    Just use a calculator for the multiplications with decimals.

  14. mathstudent55
    • one year ago
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    A. 4.3(14x+2.5) = 4.3 * 14x + 4.3 * 2.5 Use a calculator for 4.3 * 14 and for 4.3 * 2.5

  15. mathstudent55
    • one year ago
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    A. 4.3(14x+2.5) = 4.3 * 14x + 4.3 * 2.5 = 60.2x + 10.75

  16. mathstudent55
    • one year ago
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    You can tell already that A and D are not the same.

  17. mathstudent55
    • one year ago
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    Now let's try B. We need to distribute again. B. 14(4.3x+2.5) = 14 * 4.3x + 14 * 2.5 Can you finish the expression above by doing the two multiplications?

  18. anonymous
    • one year ago
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    I got 95.2 by adding the sums of the two multiplications.

  19. mathstudent55
    • one year ago
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    No. You can add the two quantities. One has x and one has no x. The are not like quantities, so you can add them. B. 14(4.3x+2.5) = 14 * 4.3x + 14 * 2.5 = 60.2x + 35

  20. mathstudent55
    • one year ago
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    So far we have: A. 60.2x + 10.75 B. 60.2x + 35 C. D. 60.2x + 2.5 None of them are equivalent. We must find what C is equal to.

  21. mathstudent55
    • one year ago
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    C. 20.6x+28+39.6x+7 You can only combine like terms. Terms with x are like terms. You can combine them together. Terms with no x are like terms. You can combine them together. You cannot combine together terms with x and terms without x.

  22. mathstudent55
    • one year ago
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    Examples: 2x + 5x = 7x 2 + 5x = 2 + 5x 5 + 2x + 3 + 4x = 5 + 3 + 2x + 4x = 8 + 6x

  23. mathstudent55
    • one year ago
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    Do you understand the idea of like and unlike terms now?

  24. anonymous
    • one year ago
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    Yes

  25. mathstudent55
    • one year ago
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    Let's try C. now. First we move the like terms together. Then we combine like terms. C. 20.6x+28+39.6x+7 = 20.6x + 39.6x + 28 + 7 Ok so far? All I did was rearrange the terms.

  26. anonymous
    • one year ago
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    Yes

  27. mathstudent55
    • one year ago
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    Now we combine the like terms with x: 20.6x + 39.6x = 60.2x and we combine the like terms without x: 28 + 7 = 35 We get: C. 20.6x+28+39.6x+7 = 20.6x + 39.6x + 28 + 7 = 60.2x + 35

  28. mathstudent55
    • one year ago
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    Now we can write what all the choices are equal to: A. 60.2x + 10.75 B. 60.2x + 35 C. 60.2x + 35 D. 60.2x + 2.5 Now it's obvious which 2 expressions are equivalent.

  29. anonymous
    • one year ago
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    Ty for your help and sry I went in and out of the conversation. There is a weird glitch that wont let me type after I send a reply. Thank you!

  30. mathstudent55
    • one year ago
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    You're welcome.

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