CAN SOMEONE TELL ME IF THESE ARE CORRECT!! ANWSER ARE ON THE BOTTOM Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work. Part B: Factor x2 + 10x + 25. Show your work. Part C: Factor x2 − 36. Show your work. -------------------- Part A-y^2(3x^2y^2-2x-8) Part B-(x+5)^2 Part C-(x+6)(x-6)

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CAN SOMEONE TELL ME IF THESE ARE CORRECT!! ANWSER ARE ON THE BOTTOM Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work. Part B: Factor x2 + 10x + 25. Show your work. Part C: Factor x2 − 36. Show your work. -------------------- Part A-y^2(3x^2y^2-2x-8) Part B-(x+5)^2 Part C-(x+6)(x-6)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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if you have 3 different typez of chocolates in the boxand u will take out all of 3 how many will left in the box ?
0
yes right so factor menas take out common stuff right so first question when you take out y^2 from first term how many y will left in the parentheses \[\huge\rm 3x^2y^2 − 2xy^2 − 8y^2\]

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Other answers:

or in other words divide all 3 terms by common factor
\[ \huge\rm \frac{ 3x^2y^2 }{ y^2 }-\frac{ 2xy^2 }{ y^2}-\frac{ 8y^2 }{ y^2 }\]
So the y^2 would cancel out?
YEP!
so y^2(??????????????)
so it would be 3x^2-2x-8?
btw Part B-(x+5)^2 \(\checkmark\) Part C-(x+6)(x-6) \(\checkmark\)
thank you
yep my pleasure
so the final answer would be 3x^2-2x-8
who kidnapped y^2 ??
y^2(3x^2-2x-8)
lO_Oks gO_Od
THANKKK YOUUU SOOO MUCHHHHH
hmmm
now factor 3x^2 -2x-8
hmmmm combine like terms first right?
are there any *like* terms ?
nope there are none
so i would apply *Headphone* method find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term a=leading coefficient b=middle term c=constant term
\[\huge\rm \color{reD}{A}x^2-\color{blue}{B}x-\color{green}{C }\] \[\huge\rm \color{reD}{3}x^2-\color{blue}{2}x-\color{green}{8 }\]
so suntract them?
no what is a and c ?
3-8?
yep a =3 and c=-8 so multiply them ac =3 times -8 = -24 find two number if you multiply them you should get -24 and if you add or subtract them you should get -2
so the answer is y^2(3x+4)(x-2)
yep that's right ..........
thankk youu
my pleasure

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