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egracer
 one year ago
CAN SOMEONE TELL ME IF THESE ARE CORRECT!! ANWSER ARE ON THE BOTTOM
Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work.
Part B: Factor x2 + 10x + 25. Show your work.
Part C: Factor x2 − 36. Show your work.

Part Ay^2(3x^2y^22x8)
Part B(x+5)^2
Part C(x+6)(x6)
egracer
 one year ago
CAN SOMEONE TELL ME IF THESE ARE CORRECT!! ANWSER ARE ON THE BOTTOM Part A: Factor 3x2y2 − 2xy2 − 8y2. Show your work. Part B: Factor x2 + 10x + 25. Show your work. Part C: Factor x2 − 36. Show your work.  Part Ay^2(3x^2y^22x8) Part B(x+5)^2 Part C(x+6)(x6)

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3if you have 3 different typez of chocolates in the boxand u will take out all of 3 how many will left in the box ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yes right so factor menas take out common stuff right so first question when you take out y^2 from first term how many y will left in the parentheses \[\huge\rm 3x^2y^2 − 2xy^2 − 8y^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3or in other words divide all 3 terms by common factor

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[ \huge\rm \frac{ 3x^2y^2 }{ y^2 }\frac{ 2xy^2 }{ y^2}\frac{ 8y^2 }{ y^2 }\]

egracer
 one year ago
Best ResponseYou've already chosen the best response.0So the y^2 would cancel out?

egracer
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 3x^22x8?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0btw Part B(x+5)^2 \(\checkmark\) Part C(x+6)(x6) \(\checkmark\)

egracer
 one year ago
Best ResponseYou've already chosen the best response.0so the final answer would be 3x^22x8

egracer
 one year ago
Best ResponseYou've already chosen the best response.0THANKKK YOUUU SOOO MUCHHHHH

egracer
 one year ago
Best ResponseYou've already chosen the best response.0hmmmm combine like terms first right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3are there any *like* terms ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3so i would apply *Headphone* method find two number if you multiply them you should get product of AC and if you add or subtract them you should get middle term a=leading coefficient b=middle term c=constant term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\huge\rm \color{reD}{A}x^2\color{blue}{B}x\color{green}{C }\] \[\huge\rm \color{reD}{3}x^2\color{blue}{2}x\color{green}{8 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yep a =3 and c=8 so multiply them ac =3 times 8 = 24 find two number if you multiply them you should get 24 and if you add or subtract them you should get 2

egracer
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is y^2(3x+4)(x2)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yep that's right ..........
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