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anonymous
 one year ago
I'm confused a little...
How does the integral of secxtanx = secx ?
anonymous
 one year ago
I'm confused a little... How does the integral of secxtanx = secx ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really? XD lol Then what is is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sec(theta)=\[\frac{ 1 }{ \cos*theta}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3if y = sec(x), then dy/dx = sec(x)*tan(x) take this in reverse to get \[\Large \int(\sec(x)\tan(x))dx = \sec(x) + C\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh right! That makes sense!!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3if you had no idea that dy/dx = sec(x)*tan(x) then you can convert sec(x)*tan(x) into (1/cos)*(sin/cos) which becomes sin/(cos^2) from there you use usub u = cos(x) du = sin(x)dx

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0that's one of the standard derivative definitions... The derivative of secx is secxtanx the antiderivative of secxtanx is secx.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I would've had to go through it with usub... i didn't know that dy/dx of secx = secxtanx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right! Thanks you guys! That really helped!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you're welcome
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