anonymous
  • anonymous
I'm confused a little... How does the integral of secxtanx = secx ?
Mathematics
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anonymous
  • anonymous
I'm confused a little... How does the integral of secxtanx = secx ?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
it doesnt ._.
anonymous
  • anonymous
Really? XD lol Then what is is?
anonymous
  • anonymous
it*

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anonymous
  • anonymous
sec(theta)=\[\frac{ 1 }{ \cos*theta}\]
anonymous
  • anonymous
Right
jim_thompson5910
  • jim_thompson5910
if y = sec(x), then dy/dx = sec(x)*tan(x) take this in reverse to get \[\Large \int(\sec(x)\tan(x))dx = \sec(x) + C\]
anonymous
  • anonymous
Ohhh right! That makes sense!!
jim_thompson5910
  • jim_thompson5910
if you had no idea that dy/dx = sec(x)*tan(x) then you can convert sec(x)*tan(x) into (1/cos)*(sin/cos) which becomes sin/(cos^2) from there you use u-sub u = cos(x) du = -sin(x)dx
UsukiDoll
  • UsukiDoll
that's one of the standard derivative definitions... The derivative of secx is secxtanx the antiderivative of secxtanx is secx.
anonymous
  • anonymous
Yeah I would've had to go through it with u-sub... i didn't know that dy/dx of secx = secxtanx
anonymous
  • anonymous
Right! Thanks you guys! That really helped!
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
:)

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