Determine the ratio of the relativistic to the non relativistic kinetic energy when V=1.5x10^-3 m/s and when V = 0.97 m/s. I have tried it three times and for some reason my answer is always zero

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Determine the ratio of the relativistic to the non relativistic kinetic energy when V=1.5x10^-3 m/s and when V = 0.97 m/s. I have tried it three times and for some reason my answer is always zero

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[KE _{rel}=mc ^{2}(\gamma-1)\] \[KE _{nonrel}=\frac{ 1 }{ 2 }mV ^{2}\]
Looks like fun, can you show your work please?
\[\gamma = \frac{ 1 }{ \sqrt{1-\left( \frac{ v }{ c } \right)}^2 }\] just to note the Lorentz factor

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Sure
1 Attachment
It's probably best if you do the calculations separately
\[KE_{rel} = mc^2\left( \frac{ 1 }{ \sqrt{1-\left( \frac{ v }{ c } \right)^2} }-1 \right)\]
You should find what fraction of the speed of light the given velocities are and then you can find the ratio.
So \[1.5 \times 10^{-3} m/s = \frac{ 1 }{ 450,000 } c \]
\[\gamma = \frac{ 1 }{ \sqrt{1-\left( \frac{ (1/450,000)c)^2 }{ c^2 } \right)} }\]
The reason you're getting 0 is, when you subtract by 1 using a calculator it's approximating to 1 as the numbers are so small, we get something insane such as 0.9999999...
for small velocities (v<

Not the answer you are looking for?

Search for more explanations.

Ask your own question