anonymous
  • anonymous
Can someone please explain in the simplest way how to solve this? Michelle rode her bicycle from her house to school at an average speed of 8 miles per hour. Later that daym she rode school back home along the same route at an average speed of 12 miles per hour. If the round trip took her 1 hour, how many miles is the round trip?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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misty1212
  • misty1212
Hi!!
misty1212
  • misty1212
don't you hate word problems?
misty1212
  • misty1212
we can do it though for sure

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More answers

anonymous
  • anonymous
ok, thanks!
misty1212
  • misty1212
we are gong to use distance equals rate time time time, or time is distance divide by rate
misty1212
  • misty1212
we don't know what the distance is, so lets call it D
misty1212
  • misty1212
time going it \[\frac{D}{8}\]right?
anonymous
  • anonymous
yes..
misty1212
  • misty1212
and time returning is?
anonymous
  • anonymous
D/12
misty1212
  • misty1212
right so total time is \[\frac{D}{8}+\frac{D}{12}\] which your are told is 1
misty1212
  • misty1212
solve \[\frac{D}{8}+\frac{D}{12}=1\] for \(D\) and you are done
misty1212
  • misty1212
do you know how to do that?
misty1212
  • misty1212
oh btw they ask for the round trip, so once you find D the answer is actually 2D
anonymous
  • anonymous
Do we need to find a common denominator first?
misty1212
  • misty1212
you can to that and then add probably be easier to multiply both sides by the least common multiple of 8 and 12 which is 24 that will clear the annoying fractions
anonymous
  • anonymous
I did it the first way because it was easier for me, I got D = 4.8
misty1212
  • misty1212
i didn't do it, let me check
anonymous
  • anonymous
And then 2*4.8 = 9.6. Thank you so much for helping!
misty1212
  • misty1212
if you multiply by 24 you get \[3 d+2 d=24\\ 5D=24\\ D=4.8\] yeah you are righ t
misty1212
  • misty1212
\[\color\magenta\heartsuit\]
anonymous
  • anonymous
that was extremely helpful. thank you again. :)
misty1212
  • misty1212
you are quite welcome

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