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speed of m/s in s

\[F = ma = \frac{ mv }{ t }\] where the mass of an electron is \[\approx 9.11 \times 10^{-31} kg\]

is used Ep=Ek is that correct?

Eelectron=Eproton? or am i overthinking it ?

Well you need the force

can i do hf=1/2mv^2?

i think i am getting confused bettween force and freunecy

Yes, you are, what you're doing wouldn't make sense, that deals with the photoelectric effect.

So for our case we have \[F = ma = \frac{ mv }{ t }\]

btw do u know the component method when doing momentum questions?

As in x and y directions

But yes, I know momentum, and how to deal with the problems.

ok hold one i will get more probs

i know E=Ef-Ei

in a glass vacuum electrons are accelatred trough a large potential difference

sorry 0.234nm

I agree with @Astrophysics

no i am done that question i am talkign about the new one

like from in glass vaccum

I see only initial data, what quantity is requested to compute, please?

The angle of first order maximum is ?

we have to apply teh Bragg's formula:
\[n\lambda = 2d\sin \theta \]

where n=1

idk about braggg but we did the compton effect

\lambda is given by the De Broglie relationship:
\[\Large \lambda = \frac{h}{p}\]

the Compton effect is related to a collision between a photon and a free electron

ok

what to do next

I think that your exercise is related to the diffraction by electrons

the energy of the electrons, is:
\[\Large E = \frac{{{p^2}}}{{2{m_e}}}\]

^?

oh r u doing somthing like Ep=Ek

it is a simple substitution

ok

2.188*10^-9

I got this:
\[\Large E = eV = 1.6 \times {10^{ - 19}} \times 615 = 9.84 \times {10^{ - 17}}joules\]

angle?

please complete, what do you get?

1.33*10^-23

coorrect!

correct!*

angle?

4.94*10^-11

that's right!

angle?

0.06049

6.05

i am in the end

from this the angle is 6.04 but the answer is 122

yes! we get:
\[\theta = 6.06\;{\text{degrees}}\]

122 degrees?

please wait I check my computations

I got the same result