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anonymous

  • one year ago

Will medal! Solve: 6/(x-3)=3/x for x and determine if the solution is extraneous.

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  1. anonymous
    • one year ago
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    x = -2, extraneous x = -2, non-extraneous x = -3, non-extraneous x = -3, extraneous

  2. anonymous
    • one year ago
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    x= -3 I'm not sure but I think it would non-extraneous

  3. anonymous
    • one year ago
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    When you plug that in you would get -1=-1 so hence the solution is non-extranoeus right?

  4. anonymous
    • one year ago
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    Could you help with this one too?

  5. anonymous
    • one year ago
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    x = 3, non-extraneous x = 3, extraneous x = -3, extraneous x = -3, non-extraneous

  6. anonymous
    • one year ago
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    Wait, what was the question? :o

  7. anonymous
    • one year ago
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    Okay whoops

  8. anonymous
    • one year ago
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    3/(x-3)=(x/x-3)-(3/2)

  9. anonymous
    • one year ago
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    3/(x-3)=(x/x-3)-(3/2)

  10. anonymous
    • one year ago
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    3/(x-3) - x/(x-3) = - (3/2) (3 - x) / (x - 3) = - (3/2) 3 - x = -3/2 (x-3) 3 - x = -(3/2)x + 9/2 6 - 2x = -3x + 9 x = 3

  11. anonymous
    • one year ago
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    I think it would x = 3 would be extraneous? I'm not quite sure.

  12. anonymous
    • one year ago
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    yup thats what i got

  13. anonymous
    • one year ago
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    Thanks so much :D

  14. anonymous
    • one year ago
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    You're welcome! :)

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