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anonymous
 one year ago
Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance?
2.14 x 106 J/g·K
2.19 x 100 J/g·K
5.73 x 104 J/g·K
2.69 x 103 J/g·K
If someone could tell me how to do it as well, it would be greatly appreciated.
anonymous
 one year ago
Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance? 2.14 x 106 J/g·K 2.19 x 100 J/g·K 5.73 x 104 J/g·K 2.69 x 103 J/g·K If someone could tell me how to do it as well, it would be greatly appreciated.

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.3\[q=mc \Delta T\]

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.3q is energy, m is mass, c is specific heat, delta T is change in temp

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So would the answer then be B?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.3If that is 2.19 x 10^0 J/(g K), yep :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Cool, thanks for your help!

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.3No worries :)
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