anonymous
  • anonymous
Given 28.2 grams of an unknown substance, if the substance absorbs 2165 joules of energy and the temperature increases by 35 Kelvin, what is the specific heat of the substance? 2.14 x 106 J/g·K 2.19 x 100 J/g·K 5.73 x 10-4 J/g·K 2.69 x 103 J/g·K If someone could tell me how to do it as well, it would be greatly appreciated.
Thermodynamics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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JoannaBlackwelder
  • JoannaBlackwelder
\[q=mc \Delta T\]
JoannaBlackwelder
  • JoannaBlackwelder
q is energy, m is mass, c is specific heat, delta T is change in temp
anonymous
  • anonymous
So would the answer then be B?

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JoannaBlackwelder
  • JoannaBlackwelder
If that is 2.19 x 10^0 J/(g K), yep :-)
anonymous
  • anonymous
Cool, thanks for your help!
JoannaBlackwelder
  • JoannaBlackwelder
No worries :-)

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