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anonymous
 one year ago
VERIFY THE IDENTITY:
1/csc(x1) + 1/csc(x+1)=2/csc(x)sin(x)
anonymous
 one year ago
VERIFY THE IDENTITY: 1/csc(x1) + 1/csc(x+1)=2/csc(x)sin(x)

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freckles
 one year ago
Best ResponseYou've already chosen the best response.1question is it really: \[\frac{1}{\csc(x1)}+\frac{1}{\csc(x+1)}=\frac{2}{\csc(x)}\sin(x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0close, only it says 2/csc(x)sin(x) not sure if that is the same thing or not?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1isn't that what I typed for the right hand side?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1did you mean to write 2/(csc(x)sin(x)) instead?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{\csc(x1)}+\frac{1}{\csc(x+1)}=\frac{2}{\csc(x)\sin(x)}\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1that doesn't seem like an identity

freckles
 one year ago
Best ResponseYou've already chosen the best response.1both sides aren't the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok that is what I kept coming up with, I just wanted to verify that it was not an identity, thank you!

freckles
 one year ago
Best ResponseYou've already chosen the best response.1did you mean to write \[\frac{1}{\csc(x)1}+\frac{1}{\csc(x)+1}=\frac{2}{\csc(x)\sin(x)}\] this is an identity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I cannot figure out how it is an identity, however....

freckles
 one year ago
Best ResponseYou've already chosen the best response.1so is that not what you are trying to prove is an identity ? it really is the first equation you wrote?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1If you really meant to write that last thing I wrote, try combining the fractions on the left hand side first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I am typing it wrong, this is exactly how it is written on the worksheet: \[\frac{ 1 }{ \csc x1 }+\frac{ 1 }{ \csc x+1 }=\frac{ 2 }{ \csc x\sin x }\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1then all you have to do is divide both top and bottom by csc(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.12 steps really: combine fractions divide top and bot by csc(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How can you combine the fractions when the denominator are not the same? I am not sure how to make them the same

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[LHS=\frac{1}{\csc(x)1}+\frac{1}{\csc(x)+1}\\ =\frac{1}{\csc(x)1}\times\frac{\csc(x)+1}{\csc(x)+1}+\frac{1}{\csc(x)+1}\times\frac{\csc(x)1}{\csc(x)1}\\ =\frac{2\csc(x)}{\csc^2(x)1}\\ =\] now divide both numerator and denominator by csc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like this? \[\frac{ 2 }{ \csc x1}\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 2 }{ \csc x\tfrac1{\csc(x)}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh of course. I understand now. Thank you so much!

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2all clear? do you understand how we combined those fractions at the start?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, I kept trying to do it that way but for some reason I was doing the algebra wrong....I need to practice more
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