anonymous
  • anonymous
Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Make sin x = 0 and cos x =0.
anonymous
  • anonymous
@mathway can u help me with a prob
anonymous
  • anonymous
okay, then what do i do?

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anonymous
  • anonymous
Look at a unit circle and find radians/degrees that has cos x=0 or sin x=0,
anonymous
  • anonymous
Remember that in (x,y), the x is the cosine and y is the sine.
anonymous
  • anonymous
which quadrant do i look in?
anonymous
  • anonymous
All because the interval is [0,2pi).
LynFran
  • LynFran
|dw:1438148609046:dw|
LynFran
  • LynFran
|dw:1438148715430:dw|
anonymous
  • anonymous
okay, would cos x = 0 x= pi/2, 3pi/2 ?
anonymous
  • anonymous
Yes. :)
LynFran
  • LynFran
correct the 2npi is actually the period...
anonymous
  • anonymous
Now you need to find sin x= 0.
anonymous
  • anonymous
Are you taking a class on FLVS?
anonymous
  • anonymous
would then would sin x = 0 x= 0, pi, 2pi ? and yes.
anonymous
  • anonymous
Yes! This is in Module 5 in Pre-Calculus? :D
anonymous
  • anonymous
yes it is lol
anonymous
  • anonymous
Because I had this question and asked here 2 days ago!
anonymous
  • anonymous
really? coincidence much lol
anonymous
  • anonymous
Ikr, anyway, so what is the solution? x=????
anonymous
  • anonymous
x = 0, pi/2, pi, 3pi/2 ?
anonymous
  • anonymous
Great job!
anonymous
  • anonymous
thank you so much for all of your help! much appreciated!!

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