anonymous
  • anonymous
Find the sine, cosine, and tangent of 45 degrees. A. Sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2 B.Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2 C. Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1 D.Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = −1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Do you have a unit circle with you?
anonymous
  • anonymous
Find 45 degrees. |dw:1438142061197:dw|
anonymous
  • anonymous
I know it D or C

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anonymous
  • anonymous
So you are stuck with tan?
anonymous
  • anonymous
YA
anonymous
  • anonymous
Tan is - when in I and III quadrant
anonymous
  • anonymous
right?
anonymous
  • anonymous
You see, when you divide anything with the same value, the answer will always be 1.
anonymous
  • anonymous
Tan's restricted domain are Quadrants II and III.
anonymous
  • anonymous
But where is 45 degrees?
anonymous
  • anonymous
|dw:1438142303668:dw|
anonymous
  • anonymous
Did you get it?
anonymous
  • anonymous
Yup
anonymous
  • anonymous
So 45 is in the first quandrant right
anonymous
  • anonymous
@mathway
anonymous
  • anonymous
45 is in quad I right?
anonymous
  • anonymous
Yes. :) My connection was lost.
anonymous
  • anonymous
O thanks
anonymous
  • anonymous
No problem! :)

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