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anonymous

  • one year ago

Find the sine, cosine, and tangent of 45 degrees. A. Sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2 B.Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2 C. Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1 D.Sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = −1

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  1. anonymous
    • one year ago
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    Do you have a unit circle with you?

  2. anonymous
    • one year ago
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    Find 45 degrees. |dw:1438142061197:dw|

  3. anonymous
    • one year ago
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    I know it D or C

  4. anonymous
    • one year ago
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    So you are stuck with tan?

  5. anonymous
    • one year ago
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    YA

  6. anonymous
    • one year ago
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    Tan is - when in I and III quadrant

  7. anonymous
    • one year ago
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    right?

  8. anonymous
    • one year ago
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    You see, when you divide anything with the same value, the answer will always be 1.

  9. anonymous
    • one year ago
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    Tan's restricted domain are Quadrants II and III.

  10. anonymous
    • one year ago
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    But where is 45 degrees?

  11. anonymous
    • one year ago
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    |dw:1438142303668:dw|

  12. anonymous
    • one year ago
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    Did you get it?

  13. anonymous
    • one year ago
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    Yup

  14. anonymous
    • one year ago
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    So 45 is in the first quandrant right

  15. anonymous
    • one year ago
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    @mathway

  16. anonymous
    • one year ago
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    45 is in quad I right?

  17. anonymous
    • one year ago
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    Yes. :) My connection was lost.

  18. anonymous
    • one year ago
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    O thanks

  19. anonymous
    • one year ago
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    No problem! :)

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spraguer (Moderator)
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