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egbeach

  • one year ago

Find the limit of the function by using direct substitution. lim(2e^x cos x) x-> pi/2

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  1. freckles
    • one year ago
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    do you have a problem pluggin in pi/2?

  2. anonymous
    • one year ago
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    can you two help me

  3. egbeach
    • one year ago
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    i just have no idea how to solve this problem

  4. freckles
    • one year ago
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    \[\lim_{x \rightarrow \frac{\pi}{2}}2e^x \cos(x)= 2 e^{\frac{\pi}{2}} \cos(\frac{\pi}{2})\] by direct substitution we can use direct substitution since the function exists at the thing the x is approaching

  5. anonymous
    • one year ago
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    im on the problem below

  6. freckles
    • one year ago
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    can you finishing simplifying

  7. egbeach
    • one year ago
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    thats the part i am having problems with.

  8. freckles
    • one year ago
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    so you aren't sure what cos(pi/2)=?

  9. egbeach
    • one year ago
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    -1/2

  10. freckles
    • one year ago
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    how do you get that

  11. freckles
    • one year ago
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    you can use the unit circle of the calculator if you want

  12. freckles
    • one year ago
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    cos(pi/2) should be zero either way

  13. egbeach
    • one year ago
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    oh

  14. freckles
    • one year ago
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    are you good?

  15. freckles
    • one year ago
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    \[\lim_{x \rightarrow \frac{\pi}{2}}2e^x \cos(x)= 2 e^{\frac{\pi}{2}} \cos(\frac{\pi}{2}) \\ =2e^{\frac{\pi}{2}} (0)=?\]

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