anonymous
  • anonymous
The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@mathway
anonymous
  • anonymous
@vera_ewing
anonymous
  • anonymous
|dw:1438142598518:dw|

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anonymous
  • anonymous
Use Pythagorean Theorem to find the hypotenuse.
anonymous
  • anonymous
So r\[r=\sqrt{1^2+-1^2}\]
anonymous
  • anonymous
|dw:1438142694687:dw|
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
\[r=\sqrt{2}\]
anonymous
  • anonymous
so sine=\[\frac{ -1 }{ \sqrt{2} }\]
anonymous
  • anonymous
r=0.
anonymous
  • anonymous
cos=\[\frac{ 1 }{ \sqrt{2} }\]
anonymous
  • anonymous
are you sure r=0 I got \[\sqrt{2}\]
anonymous
  • anonymous
Oh shoot wait.
anonymous
  • anonymous
It is sq rt of 2. I forgot that it will be squared. :D Sorry!
anonymous
  • anonymous
Make sure you rationalize them.
anonymous
  • anonymous
what do u mean rationalize them
anonymous
  • anonymous
tan= -1
anonymous
  • anonymous
|dw:1438143031420:dw|
anonymous
  • anonymous
You don't want to have a radical sign in the denominator.
anonymous
  • anonymous
What do you rationaliz for
anonymous
  • anonymous
oh ok Iget it
anonymous
  • anonymous
So sine\[\frac{ \sqrt{2} }{ 2 }\]
anonymous
  • anonymous
Sine is a negative. :D
anonymous
  • anonymous
and cos = \[\frac{- \sqrt{2} }{ 2 }\]
anonymous
  • anonymous
and Tangent \[= -1\]
anonymous
  • anonymous
You interchanged them the sine and cosine.
anonymous
  • anonymous
Oh ya I noticed my bad
anonymous
  • anonymous
Anyway, you did it all! Great job!

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