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anonymous

  • one year ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.

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  1. anonymous
    • one year ago
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    @mathway

  2. anonymous
    • one year ago
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    @vera_ewing

  3. anonymous
    • one year ago
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    |dw:1438142598518:dw|

  4. anonymous
    • one year ago
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    Use Pythagorean Theorem to find the hypotenuse.

  5. anonymous
    • one year ago
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    So r\[r=\sqrt{1^2+-1^2}\]

  6. anonymous
    • one year ago
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    |dw:1438142694687:dw|

  7. anonymous
    • one year ago
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    Yes.

  8. anonymous
    • one year ago
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    \[r=\sqrt{2}\]

  9. anonymous
    • one year ago
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    so sine=\[\frac{ -1 }{ \sqrt{2} }\]

  10. anonymous
    • one year ago
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    r=0.

  11. anonymous
    • one year ago
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    cos=\[\frac{ 1 }{ \sqrt{2} }\]

  12. anonymous
    • one year ago
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    are you sure r=0 I got \[\sqrt{2}\]

  13. anonymous
    • one year ago
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    Oh shoot wait.

  14. anonymous
    • one year ago
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    It is sq rt of 2. I forgot that it will be squared. :D Sorry!

  15. anonymous
    • one year ago
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    Make sure you rationalize them.

  16. anonymous
    • one year ago
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    what do u mean rationalize them

  17. anonymous
    • one year ago
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    tan= -1

  18. anonymous
    • one year ago
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    |dw:1438143031420:dw|

  19. anonymous
    • one year ago
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    You don't want to have a radical sign in the denominator.

  20. anonymous
    • one year ago
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    What do you rationaliz for

  21. anonymous
    • one year ago
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    oh ok Iget it

  22. anonymous
    • one year ago
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    So sine\[\frac{ \sqrt{2} }{ 2 }\]

  23. anonymous
    • one year ago
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    Sine is a negative. :D

  24. anonymous
    • one year ago
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    and cos = \[\frac{- \sqrt{2} }{ 2 }\]

  25. anonymous
    • one year ago
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    and Tangent \[= -1\]

  26. anonymous
    • one year ago
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    You interchanged them the sine and cosine.

  27. anonymous
    • one year ago
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    Oh ya I noticed my bad

  28. anonymous
    • one year ago
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    Anyway, you did it all! Great job!

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