anonymous one year ago An acute angle θ is in a right triangle with sin θ = eight ninths. What is the value of cot θ? love giving medals to people who help!

1. anonymous

Remember that cot=cos/sin.

2. anonymous

|dw:1438145286805:dw|

3. anonymous

Use Pythagorean Theorem to solve for the other side.

4. anonymous

You there?

5. anonymous

would it be sq 9^2-8^2

6. anonymous

Yes.

7. anonymous

thats none of the answer choices

8. anonymous

Oh no, that's one of steps; not the answer. We're getting near, don't worry.

9. anonymous

|dw:1438145770329:dw|

10. anonymous

|dw:1438145807460:dw|

11. anonymous

|dw:1438145868345:dw|

12. anonymous

So what is the sine? What is the cosine?

13. anonymous

$\sin=\frac{ opposite }{ hypotenuse }; cosine=\frac{ adjacent }{ hypotenuse }$

14. anonymous

|dw:1438146075606:dw|

15. anonymous

8/sq17?

16. anonymous

What is the sine?

17. anonymous

that is the sine

18. anonymous

No. sq 17 is the adjacent, not the hypotenuse.You need opposite/hypotenuse.

19. anonymous

|dw:1438146386165:dw|

20. anonymous

oh then 8/9

21. anonymous

Yes, and what is the cosine? Cosine is adjacent/hypotenuse.

22. anonymous

Base you answer on the drawing. :)

23. anonymous

sq17/9

24. anonymous

Perfect! So now, we need to find cot.

25. anonymous

cot=cos/sin.

26. anonymous

|dw:1438146716415:dw|

27. anonymous

Can you hover on the drawing I just drew, and click "Reply using drawing" and write the cos and sin?

28. anonymous

What is the cos again? How about the sine?

29. anonymous

|dw:1438146964481:dw|

30. anonymous

Im confused because isnt the bottum line supposed to be opposite

31. anonymous

and im so sorry my computer is being really dumb

32. anonymous

Huh? Can draw the write the cos/sin? :)

33. anonymous

cot=cos/sin

34. anonymous

The bottom line of the triangle is supposed to be opposite, you put adjacent. and okay i will

35. anonymous

cot=sq17/9 / 8/9

36. anonymous

No. :(

37. anonymous

okay, i give up lol

38. anonymous

I was trolling. :(

39. anonymous

XD

40. anonymous

You're right! HAHA.

41. anonymous

ohh! yay! lol

42. anonymous

|dw:1438147400024:dw|

43. anonymous

So now, to divide this, you multiply the numerator to the reciprocal of the denominator.

44. anonymous

What is the reciprocal of 8/9?

45. anonymous

|dw:1438147459855:dw|

46. anonymous

i was wondering if the triangle should be like this tho

47. anonymous

No. I put the angle in the|dw:1438147529285:dw|

48. anonymous

Oh i see now

49. anonymous

|dw:1438147560921:dw|

50. anonymous

yeah i didnt notice you did that lol

51. anonymous

So the reciprocal of 8/9 is 9/8.

52. anonymous

yep

53. anonymous

|dw:1438147658966:dw|

54. anonymous

sq17/8!

55. anonymous

Hooray!!! :D Great job!

56. anonymous

Youre amazing!

57. anonymous

I sent you message, and you didn't reply. :(

58. anonymous

Sorry im doing an exam :( ill reply as soon as i am done! im struggling sorry.

59. anonymous

Whoops! Sorry. :) Good luck!

Find more explanations on OpenStudy