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anonymous

  • one year ago

An acute angle θ is in a right triangle with sin θ = eight ninths. What is the value of cot θ? love giving medals to people who help!

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  1. anonymous
    • one year ago
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    Remember that cot=cos/sin.

  2. anonymous
    • one year ago
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    |dw:1438145286805:dw|

  3. anonymous
    • one year ago
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    Use Pythagorean Theorem to solve for the other side.

  4. anonymous
    • one year ago
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    You there?

  5. anonymous
    • one year ago
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    would it be sq 9^2-8^2

  6. anonymous
    • one year ago
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    Yes.

  7. anonymous
    • one year ago
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    thats none of the answer choices

  8. anonymous
    • one year ago
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    Oh no, that's one of steps; not the answer. We're getting near, don't worry.

  9. anonymous
    • one year ago
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    |dw:1438145770329:dw|

  10. anonymous
    • one year ago
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    |dw:1438145807460:dw|

  11. anonymous
    • one year ago
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    |dw:1438145868345:dw|

  12. anonymous
    • one year ago
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    So what is the sine? What is the cosine?

  13. anonymous
    • one year ago
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    \[\sin=\frac{ opposite }{ hypotenuse }; cosine=\frac{ adjacent }{ hypotenuse }\]

  14. anonymous
    • one year ago
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    |dw:1438146075606:dw|

  15. anonymous
    • one year ago
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    8/sq17?

  16. anonymous
    • one year ago
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    What is the sine?

  17. anonymous
    • one year ago
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    that is the sine

  18. anonymous
    • one year ago
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    No. sq 17 is the adjacent, not the hypotenuse.You need opposite/hypotenuse.

  19. anonymous
    • one year ago
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    |dw:1438146386165:dw|

  20. anonymous
    • one year ago
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    oh then 8/9

  21. anonymous
    • one year ago
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    Yes, and what is the cosine? Cosine is adjacent/hypotenuse.

  22. anonymous
    • one year ago
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    Base you answer on the drawing. :)

  23. anonymous
    • one year ago
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    sq17/9

  24. anonymous
    • one year ago
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    Perfect! So now, we need to find cot.

  25. anonymous
    • one year ago
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    cot=cos/sin.

  26. anonymous
    • one year ago
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    |dw:1438146716415:dw|

  27. anonymous
    • one year ago
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    Can you hover on the drawing I just drew, and click "Reply using drawing" and write the cos and sin?

  28. anonymous
    • one year ago
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    What is the cos again? How about the sine?

  29. anonymous
    • one year ago
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    |dw:1438146964481:dw|

  30. anonymous
    • one year ago
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    Im confused because isnt the bottum line supposed to be opposite

  31. anonymous
    • one year ago
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    and im so sorry my computer is being really dumb

  32. anonymous
    • one year ago
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    Huh? Can draw the write the cos/sin? :)

  33. anonymous
    • one year ago
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    cot=cos/sin

  34. anonymous
    • one year ago
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    The bottom line of the triangle is supposed to be opposite, you put adjacent. and okay i will

  35. anonymous
    • one year ago
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    cot=sq17/9 / 8/9

  36. anonymous
    • one year ago
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    No. :(

  37. anonymous
    • one year ago
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    okay, i give up lol

  38. anonymous
    • one year ago
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    I was trolling. :(

  39. anonymous
    • one year ago
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    XD

  40. anonymous
    • one year ago
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    You're right! HAHA.

  41. anonymous
    • one year ago
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    ohh! yay! lol

  42. anonymous
    • one year ago
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    |dw:1438147400024:dw|

  43. anonymous
    • one year ago
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    So now, to divide this, you multiply the numerator to the reciprocal of the denominator.

  44. anonymous
    • one year ago
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    What is the reciprocal of 8/9?

  45. anonymous
    • one year ago
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    |dw:1438147459855:dw|

  46. anonymous
    • one year ago
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    i was wondering if the triangle should be like this tho

  47. anonymous
    • one year ago
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    No. I put the angle in the|dw:1438147529285:dw|

  48. anonymous
    • one year ago
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    Oh i see now

  49. anonymous
    • one year ago
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    |dw:1438147560921:dw|

  50. anonymous
    • one year ago
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    yeah i didnt notice you did that lol

  51. anonymous
    • one year ago
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    So the reciprocal of 8/9 is 9/8.

  52. anonymous
    • one year ago
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    yep

  53. anonymous
    • one year ago
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    |dw:1438147658966:dw|

  54. anonymous
    • one year ago
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    sq17/8!

  55. anonymous
    • one year ago
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    Hooray!!! :D Great job!

  56. anonymous
    • one year ago
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    Youre amazing!

  57. anonymous
    • one year ago
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    I sent you message, and you didn't reply. :(

  58. anonymous
    • one year ago
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    Sorry im doing an exam :( ill reply as soon as i am done! im struggling sorry.

  59. anonymous
    • one year ago
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    Whoops! Sorry. :) Good luck!

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