anonymous
  • anonymous
An acute angle θ is in a right triangle with sin θ = eight ninths. What is the value of cot θ? love giving medals to people who help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Remember that cot=cos/sin.
anonymous
  • anonymous
|dw:1438145286805:dw|
anonymous
  • anonymous
Use Pythagorean Theorem to solve for the other side.

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anonymous
  • anonymous
You there?
anonymous
  • anonymous
would it be sq 9^2-8^2
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
thats none of the answer choices
anonymous
  • anonymous
Oh no, that's one of steps; not the answer. We're getting near, don't worry.
anonymous
  • anonymous
|dw:1438145770329:dw|
anonymous
  • anonymous
|dw:1438145807460:dw|
anonymous
  • anonymous
|dw:1438145868345:dw|
anonymous
  • anonymous
So what is the sine? What is the cosine?
anonymous
  • anonymous
\[\sin=\frac{ opposite }{ hypotenuse }; cosine=\frac{ adjacent }{ hypotenuse }\]
anonymous
  • anonymous
|dw:1438146075606:dw|
anonymous
  • anonymous
8/sq17?
anonymous
  • anonymous
What is the sine?
anonymous
  • anonymous
that is the sine
anonymous
  • anonymous
No. sq 17 is the adjacent, not the hypotenuse.You need opposite/hypotenuse.
anonymous
  • anonymous
|dw:1438146386165:dw|
anonymous
  • anonymous
oh then 8/9
anonymous
  • anonymous
Yes, and what is the cosine? Cosine is adjacent/hypotenuse.
anonymous
  • anonymous
Base you answer on the drawing. :)
anonymous
  • anonymous
sq17/9
anonymous
  • anonymous
Perfect! So now, we need to find cot.
anonymous
  • anonymous
cot=cos/sin.
anonymous
  • anonymous
|dw:1438146716415:dw|
anonymous
  • anonymous
Can you hover on the drawing I just drew, and click "Reply using drawing" and write the cos and sin?
anonymous
  • anonymous
What is the cos again? How about the sine?
anonymous
  • anonymous
|dw:1438146964481:dw|
anonymous
  • anonymous
Im confused because isnt the bottum line supposed to be opposite
anonymous
  • anonymous
and im so sorry my computer is being really dumb
anonymous
  • anonymous
Huh? Can draw the write the cos/sin? :)
anonymous
  • anonymous
cot=cos/sin
anonymous
  • anonymous
The bottom line of the triangle is supposed to be opposite, you put adjacent. and okay i will
anonymous
  • anonymous
cot=sq17/9 / 8/9
anonymous
  • anonymous
No. :(
anonymous
  • anonymous
okay, i give up lol
anonymous
  • anonymous
I was trolling. :(
anonymous
  • anonymous
XD
anonymous
  • anonymous
You're right! HAHA.
anonymous
  • anonymous
ohh! yay! lol
anonymous
  • anonymous
|dw:1438147400024:dw|
anonymous
  • anonymous
So now, to divide this, you multiply the numerator to the reciprocal of the denominator.
anonymous
  • anonymous
What is the reciprocal of 8/9?
anonymous
  • anonymous
|dw:1438147459855:dw|
anonymous
  • anonymous
i was wondering if the triangle should be like this tho
anonymous
  • anonymous
No. I put the angle in the|dw:1438147529285:dw|
anonymous
  • anonymous
Oh i see now
anonymous
  • anonymous
|dw:1438147560921:dw|
anonymous
  • anonymous
yeah i didnt notice you did that lol
anonymous
  • anonymous
So the reciprocal of 8/9 is 9/8.
anonymous
  • anonymous
yep
anonymous
  • anonymous
|dw:1438147658966:dw|
anonymous
  • anonymous
sq17/8!
anonymous
  • anonymous
Hooray!!! :D Great job!
anonymous
  • anonymous
Youre amazing!
anonymous
  • anonymous
I sent you message, and you didn't reply. :(
anonymous
  • anonymous
Sorry im doing an exam :( ill reply as soon as i am done! im struggling sorry.
anonymous
  • anonymous
Whoops! Sorry. :) Good luck!

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