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anonymous

  • one year ago

Given the diagram above and the fact that <BCD is equal to <ADC. Show that <B is equal to <A. (please help!!)

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    What program are you doing this on?

  4. arindameducationusc
    • one year ago
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    i m here

  5. anonymous
    • one year ago
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    thank you @arindameducationusc I am so confused

  6. Owlcoffee
    • one year ago
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    On the Diagram we know that the segments BC and AD are congruent, also that the angles BCD and angle ADC are congruent. Now, you might observe that both triangles have one same side, which is CD, and we can see it clear on the name of each: T.BCD and T.ACD the fact that two of their vertices coincide means that they share a side. Now, because they share the same side, we can establish the axiom of rectivity: \[CD=CD\] Now, we know that two sides and the angle between them are congruent, this being: \[BC=AD\] \[\angle BCD = \angle ADC\] \[CD=CD\] Now with that informaton we can use the SAS theorem of congruency and we can conclude that T.BCD and T.ACD.

  7. Owlcoffee
    • one year ago
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    Since we know that the triangles are congruent, we can say for sure that: \[\angle B \cong \angle A\]

  8. arindameducationusc
    • one year ago
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    Go with @ Owlcoffee, He is good....

  9. anonymous
    • one year ago
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    Thank you @Owlcoffee I'm almost positive the answer is B, then.. Seeing how BC=AD. That was the only option in the multiple choice

  10. Owlcoffee
    • one year ago
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    The answer is not "B". Because BC=AD is given information.

  11. anonymous
    • one year ago
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    oh crap

  12. anonymous
    • one year ago
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    what are your choices?

  13. anonymous
    • one year ago
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  14. anonymous
    • one year ago
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    well you its not B. and D is also wrong... so is either A or C

  15. anonymous
    • one year ago
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    whatever, I tried lol

  16. arindameducationusc
    • one year ago
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    Its A

  17. anonymous
    • one year ago
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    yeah

  18. arindameducationusc
    • one year ago
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    cause that is common base between the triangles..... Did you get it @jillina29 ?

  19. anonymous
    • one year ago
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    Thank you both :) @arindameducationusc @nogoodatgeometry

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