anonymous
  • anonymous
Given the diagram above and the fact that
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
What program are you doing this on?

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arindameducationusc
  • arindameducationusc
i m here
anonymous
  • anonymous
thank you @arindameducationusc I am so confused
Owlcoffee
  • Owlcoffee
On the Diagram we know that the segments BC and AD are congruent, also that the angles BCD and angle ADC are congruent. Now, you might observe that both triangles have one same side, which is CD, and we can see it clear on the name of each: T.BCD and T.ACD the fact that two of their vertices coincide means that they share a side. Now, because they share the same side, we can establish the axiom of rectivity: \[CD=CD\] Now, we know that two sides and the angle between them are congruent, this being: \[BC=AD\] \[\angle BCD = \angle ADC\] \[CD=CD\] Now with that informaton we can use the SAS theorem of congruency and we can conclude that T.BCD and T.ACD.
Owlcoffee
  • Owlcoffee
Since we know that the triangles are congruent, we can say for sure that: \[\angle B \cong \angle A\]
arindameducationusc
  • arindameducationusc
Go with @ Owlcoffee, He is good....
anonymous
  • anonymous
Thank you @Owlcoffee I'm almost positive the answer is B, then.. Seeing how BC=AD. That was the only option in the multiple choice
Owlcoffee
  • Owlcoffee
The answer is not "B". Because BC=AD is given information.
anonymous
  • anonymous
oh crap
anonymous
  • anonymous
what are your choices?
anonymous
  • anonymous
anonymous
  • anonymous
well you its not B. and D is also wrong... so is either A or C
anonymous
  • anonymous
whatever, I tried lol
arindameducationusc
  • arindameducationusc
Its A
anonymous
  • anonymous
yeah
arindameducationusc
  • arindameducationusc
cause that is common base between the triangles..... Did you get it @jillina29 ?
anonymous
  • anonymous
Thank you both :) @arindameducationusc @nogoodatgeometry

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