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anonymous

  • one year ago

How do I find the missing side of an isosceles triangle if A=42 and B=42. How do I find C? A. 42° B. 69° C. 74° D. 132°

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  1. anonymous
    • one year ago
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    did you leave something out?

  2. anonymous
    • one year ago
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  3. mathstudent55
    • one year ago
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    In a triangle, if two sides are congruent, then the opposite angles are congruent. This can be restated as: The base angles of an isosceles triangle are congruent.

  4. mathstudent55
    • one year ago
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    |dw:1438149014299:dw|

  5. mathstudent55
    • one year ago
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    |dw:1438149049857:dw|

  6. anonymous
    • one year ago
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    So m<C = 42?

  7. mathstudent55
    • one year ago
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    The sum of the measures of the 3 angles is 180 deg. x + x + 42 = 180

  8. aric200
    • one year ago
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    A triangle must=180Deg

  9. mathstudent55
    • one year ago
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    No. m<C is not 42. Solve the equation below. 2x + 42 = 180 Solve for x.

  10. aric200
    • one year ago
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    If <C=42 then <B Would have to= 42 as <C and B are = To each other Meaning <A <B and <C together would = 126 deg which couldnt be possible, Dont just throw out random numbers Look at the picture surly <A Could not= <C

  11. aric200
    • one year ago
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    I am going to put in in simple terms. O kay <C and <B must be the same or = each other. We know <A is 42 Degrees and can not= the same as <C and B. So to Find Do 180-42 Because a triangle= 180 and we already know m<A You will get 138 Now Divide by 2 because there are 2 angles left/ <C and <B You will get 69 So < C and <B both = 69 <C =69

  12. anonymous
    • one year ago
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    Thank you @aric200 ! :)

  13. mathstudent55
    • one year ago
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    2x + 42 = 180 2x = 138 x = 69

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